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2 years ago

A rock is at the top of a 20m tall hill. The rock has a mass of 10kg. How much potential energy does the rock have?

Physics

2 answers:

Rashid [163]2 years ago

4 0

Answer:

Ggghhhjhhhhhbdufdusty

Ivenika [448]2 years ago

4 0

Answer:

2000 Joules

Explanation:

The formula for potential energy is P.E.=mgh (where M is Mass, G is acceleration due to Gravity, and H is Height)

Plug the numbers in to get P.E.=(10kg)(10m/s^2)(20m)

Multiply together to get 2000 joules

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A 0.105- kg hockey puck moving at 24 m/s is caught and held by a 75-kg goalie at rest. With what speed does the goalie slide on

Veseljchak [2.6K]

Answer:

0.03 m/s

Explanation:

Applying law of conservation of momentum,

m₁v₁ + m₂v₂ = (m₁ + m₂)v
0.105(24) + 75(0) = (0.105 + 75)v
75.105v = 2.52
v = 2.52/75.105
v = 0.03 m/s

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2 years ago

A circular dartboard has a radius of 2 meters and a red circle in the center. Assume you hit the target at a random point. For w

Sati [7]

Answer:

1.549 m

Explanation:

Given:

The radius of the circular board, r = 2 m

The probability of hitting the red is given as 0.6

Now, this probability of hitting the red can be conclude as

0.6 = (Area of red)/ (Total area of the board)

Total area of the board = πr² = π × 2²

let the radius of the red area be R

thus, area of red circle, = πR²

on substituting the value of the area, we have

0.6 = (πR²)/ (π × 2²)

R² = 2.4

R = 1.549 m

Thus, the radius of the red circle is 1.549 m

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3 years ago

A centrifuge in a medical laboratory rotates at an angular speed of 3,500 rev/min, clockwise (when viewed from above). When swit

Ratling [72]

Answer:

The magnitude of angular acceleration is $232.38\ rad/s^2$ .

Explanation:

Given that,

Initial angular velocity, $\omega_i=3500\ rev/min=366.5\ rad/s$

When it switched off, it comes o rest, $\omega_f=0$

Number of revolution, $\theta=46=289.02\ rad$

We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :

$\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{-(366.51)^2}{2\times 289.02}\\\\\alpha =-232.38\ rad/s^2$

So, the magnitude of angular acceleration is $232.38\ rad/s^2$ . Hence, this is the required solution.

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3 years ago

A positively charged plastic ruler is brought close to a piece paper resting on the desk. The piece of paper was initially neutr

stealth61 [152]

Answer: static electricity

Explanation:

When the plastic ruler is rubbed, friction opposes the motion and causes the transfer of electron from one surface to another such that plastic becomes negatively charged. When ruler is brought nearer to the paper, it induces the positive charge in the piece of paper.

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3 years ago

Sophie says that geologic maps do not matter because she gets no benefits from them. Why is Sophie wrong? a. She can see the ran

astra-53 [7]

The Answer is Option C
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3 years ago

Read 2 more answers