Ba(OH)2 is an basic solution. It has more OH- ions than H+ ions. pOH should be calculated to find out its pH
The reaction is
Ba(OH)2 ⇒ Ba2+ (aq) + 2 OH-(aq)
One mole barium hydroxide releases 2 moles hydroxide ions.
Use that ratio to calculate molarity (M) of OH- ions [OH-]. The ratio is 1:2.
0.10 M Ba(OH)2 release 2*0.10 M= 0.02 M OH- ions
[OH-]= 0.02
pOH= - log [OH-] = - log 0.02 = 1.7
Thats not the answer! We found pOH of the solution before titration.
pH and pOH relationship is shown by formula of pH+pOH= 14
pH= 14-pOH
pH= 14-1.7= 12.3
The pH of a buffer solution with acid that (PKA 6. 1) is exactly half as concentrated as its conjugate base is 6.4.
<h3>What is a buffer solution?</h3>
A buffer solution is a solution that has a maintained pH, not basic or not acidic. Its pH changes when acid or base is added to the solution.
We had to figure out the acid's concentration, which is exactly half that of its potential base.
We know that pH = pH_log
We have less than 6.1 pH so this is a conjugated base.
This will equal to 6.1 + log2 = 6.4
Thus, the pH of a buffer solution with acid is 6.4.
To learn more about buffer solutions, refer to the below link:
brainly.com/question/13169083
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The answer I'm pretty sure is a because it can't be d because ionic binding the electrons are affected and it can't be c because that's covalent bonding and it can't be b because they don't swap electrons.
Answer:
is the value of the equilibrium constant at this temperature.
Explanation:
We are given:
Partial pressure of 
Partial pressure of 
Partial pressure of 
The expression of 
for the given chemical equation is:
Putting values in above equation, we get:
is the value of the equilibrium constant at this temperature.
Answer:
A liquid will flow only sideways and down
Explanation:
