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maksim [4K]
3 years ago
12

Calculate the volume of 5.00 mol of helium at 120C and 1520 mm Hg

Chemistry
1 answer:
levacccp [35]3 years ago
4 0

Answer:

80.7 L

Step-by-step explanation:

This looks like a case where we can use the Ideal Gas Law to calculate the volume.

pV = nRT       Divide both sides by p

V = (nRT)/p

=====

Data:

n = 5.00 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = (120 +273.15) K = 393.15K

p = 1520 mmHg × 1 atm/760 mmHg = 2.00 atm

=====

Calculation:

V = (5.00 × 0.082 06 × 393.15)/2.00

V = 161.3/2.00

V = 80.7 L  

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May someone assist, please...? I don't know how to do chemistry work...
EastWind [94]

Answer:

1) 90.0 mL

2) 11.25 M

3) 0.477 M

4) 144 mL

Explanation:

The main formula that will be used for all these calculations is:

                                                     C₁V₁ = C₂V₂

C stands for concentration and V stands for volume and the subscripts 1 and 2 indicate an initial concentration or volume and a final concentration or volume.

For each problem, it's best to start by figuring out what you have and what you need to find. Figure out if you're looking for an initial value or a final value.

1) We need to find the initial volume. So, take what values you have and plug them in and then solve for whatever variable:

5.00 M · V₁ = 500.0mL · 0.900 M                        - divide by 5.00

C₁ = 90.0 mL

2) This time we're finding the initial concentration:

20.0mL · C₁ = 150.0mL · 1.50 M                          - divide by 20.0mL

C₂ = 11.25 M

3) Now we're finding the final concentration:

12.00mL · 3.50 M = 88.0mL · C₂                         - divide by 88.0mL

C₂ = 0.477 M

4) Finally, we're looking for the final volume:

9.0mL · 8.0 M = 0.50 M · V₂                                - divide by 0.50 M

V₂ = 144mL

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