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Brut [27]
3 years ago
7

What are stepdown transformers used for

Physics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

Step down transformers are used in power adaptors and rectifiers to efficiently decrease the voltage. They are also used in electronic SMPS.

Explanation:

pls mark me as brainlist

Thanks a lot

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An iron weight, suspended by a string, is motionless. The tension in the string is 4.75 newtons. What is the mass of the iron we
kakasveta [241]
Since weight is motionless, net force is equal to zero.
According to Newton's 2nd law of motion,

T - mg = 0-----------(T = tension, mg = weight of mass)

4.75 = m x 9.8
m = 4.75/9.8

m = 0.48 kg.

Hope this helps\!
7 0
3 years ago
What minimum speed does a 100 g puck need to make it to the top of a 4.60 m -long, 24.0 ∘ frictionless ramp?
mash [69]

Answer:

6.05 m/s

Explanation:

In order for the puck to reach the top of the ramp, its initial kinetic energy must be equal to its final potential energy.

So we can write:

KE=PE\\\frac{1}{2}mv^2 = mgh (1)

where

m = 100 g = 0.1 kg is the mass of the puck

v is the initial speed of the puck

g=9.8 m/s^2 is the acceleration due to gravity

h is the height of the ramp

Here we know that

d = 4.60 m is the length of the ramp

\theta=24.0^{\circ} is the angle of the ramp

So its height is

h=d sin \theta = (4.60)(sin 24.0^{\circ})=1.87 m

So now we can re-arrange eq (1) to find the minimum speed of the puck:

v=\sqrt{2gh}=\sqrt{2(9.8)(1.87)}=6.05 m/s

4 0
3 years ago
The absolute magnitude of a star________.
serg [7]
<span>The absolute magnitude of a star is how bright it would appear to us
if it were located ten parsecs (about 32.6 light years) from us.  So it's
a way of treating all stars equally ... on a "level playing field" ... and it
describes each star's actual brightness. </span>
8 0
3 years ago
С
Lelechka [254]

Answer:

a = 0.8 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration, in this way we come to the following equation:

∑F = m*a

where:

F = forces applied [N]

m = mass = 1000 [kg]

a = acceleration [m/s²]

Now using Newton's second law.

1200 - 400 = 1000*a\\800 = 1000 *a\\a=0.8[m/s^{2} ]

8 0
3 years ago
I don't really need this question answered, I just need someone to help explain to me what it's asking me. To me, it's worded ve
Evgen [1.6K]
Technically it’s asking what will happen to the skaters height it will rise to (the skaters highest point) if you change the initial height. Is this what you needed?
8 0
3 years ago
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