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2 years ago

What are stepdown transformers used for

Physics

1 answer:

lesya692 [45]2 years ago

7 0

Answer:

Step down transformers are used in power adaptors and rectifiers to efficiently decrease the voltage. They are also used in electronic SMPS.

Explanation:

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A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is

Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration $a_{c}$ is given by the following equation:

$a_{c}=\frac{V^{2}}{r}$ (1)

Where:

$a_{c}=17 m/s^{2}$ is the <u>centripetal acceleration</u>

$V$ is the<u> tangential speed</u>

$r=12 m$ is the <u>radius</u> of the circle

Isolating $V$ from (1):

$V=\sqrt{a_{c}r}$ (2)

$V=\sqrt{(17 m/s^{2})(12 m)}$

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Finally:

$V=14.28 m/s$ This is the girl's tangential speed

3 0

3 years ago

Assume charge builds up on the cloud and on the ground until a uniform electric field of 4.00 ✕ 106 N/C throughout the space bet

kumpel [21]

Answer:

The value of the maximum charge the cloud can hold Q = 177.08 coulomb

Explanation:

Given data

Electrical Field E = 4 × $10^{6}$ $\frac{N}{C}$

the maximum charge the cloud can hold is given by

Q = E A x ---- (1)

where A = area = 5 × $10^{6}$

x = electrical Permittivity of air = 8.854 × $10^{-12}$

Q = (4 × $10^{6}$ ) (5 × $10^{6}$ ) ( 8.854 × $10^{-12}$ )

Q = 177.08 coulomb

This is the value of the maximum charge the cloud can hold.

6 0

3 years ago

Which is an example of an abiotic factor in a pond environment?

vesna_86 [32]

"Non-Living" things are known as "Abiotic factor" in the ecosystem.

In short, Your Answer would be: Option A) The Water

Hope this helps!

3 0

3 years ago

Read 2 more answers

If you drop a ball off a cliff, it starts out at 0 m/s. after 1 s, it will be traveling at about 10 m/s. if air resistance is re

anastassius [24]

The ball dropped of a cliff will have a final velocity of 19.6 m/s at 2s

The free fall formula and the procedure we will use is:

fv = g* t

Where:

fv = final velocity
g = acceleration due to gravity
t = time taken
h = height traveled

Information of the problem:

g = 9.8 m/s².
t = 2 s
vf = ?

Applying final velocity formula we get:

fv = g* t

fv = 9.8 m/s² * 2 s

fv = 19.6 m/s

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

Learn more about free fall at brainly.com/question/11257529

#SPJ4

5 0

1 year ago

I need help on 1. B and show work

Nata [24]

Acceleration = (end speed minus beginning speed) divided by (time for the change).

4 0

3 years ago