Ask question

Ask question

All categories

3 years ago

13

A disk with a hole has inner radius rin and outer radius rout. the disk is uniformly charged with total charge q. find an expres

sion for the on-axis electric potential at distance z from the center of the disk

1 answer:

Effectus [21]3 years ago

3 0

Here it is. I used the surface charge density σ as q/Area, and then wrote it out in terms of q at the end

You might be interested in

A physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Teflon frying p

Semenov [28]

Answer:

$f_n=3.75N$

Explanation:

From the question we are told that:

Frictional force $F=0.150N$

Coefficient of kinetic friction $\mu=0.04$

Generally the equation for Normal for is mathematically given by

$f_n=\frac{F}{\mu}$

Therefore

$f_n=\frac{0.150}{0.04}$

$f_n=3.75N$

5 0

2 years ago

Psychological profiling is also known as criminal profiling. True or False?

Nikolay [14]

So my opinion that is false bc. the psychological profiling not is necessary being as criminal profiling ,the criminal mean a greater,intensive word in the way of ,,killer" ,when the ,,psychological" profile is total different way

hope helped

8 0

3 years ago

Read 2 more answers

A constant torque is applied to a rigid wheel whose moment of inertia is 2.0 kg · m2 around the axis of rotation. If the wheel s

Jlenok [28]

Answer:

The applied torque is 3.84 N-m.

Explanation:

Given that,

Moment of inertia of the wheel is $2\ kg-m^2$

Initial speed of the wheel is 0 (at rest)

Final angular speed is 25 rad/s

Time, t = 13 s

The relation between moment of inertia and torque is given by :

$\tau=I\alpha \\\\\tau=I\times \dfrac{\omega_f}{t}\\\\\tau=2\times \dfrac{25}{13}\\\\\tau=+3.84\ N-m$

So, the applied torque is 3.84 N-m.

4 0

3 years ago

What are four minerals that are commonly taken from ores

Umnica [9.8K]

If it helps or doesn't I'm sorry, but if you even played the game Minecraft just remember it.

Gold, silver, coal, and iron come from ores.

5 0

3 years ago

It takes 20 N of force to move a box a distance of 10 m. How much work is done on the box?

PIT_PIT [208]

Answer:

Ans is 200 J

Explanation:

Given: Force = 20N

Distance = 10m

Work done = Force * displacement

= 20 * 10

= 200 J

3 0

3 years ago