Answer:
8721.132 Kg.
Explanation:
The following data were obtained from the question:
Density (D) of silver = 10.5 g/cm³
Length (L) of silver = 0.94 m
Mass (m) of silver =.?
Next, we shall determine the volume of silver. This can be obtained as follow:
Volume = Length × Length × Length
Volume = L × L × L
Volume = L³
Length (L) of silver = 0.94 m
Volume (V) of silver =?
Volume (V) of silver = 0.94³
Volume (V) of silver = 0.830584 m³
Next, we shall convert 0.830584 m³ to cm³. This can be obtained as follow:
1 m³ = 1×10⁶ cm³
Therefore,
0.830584 m³ = 0.830584 m³ / 1 m³ × 1×10⁶ cm³
0.830584 m³ = 830584 cm³
Therefore, 0.830584 m³ is equivalent 830584 cm³.
Thus, the volume of the silver is 830584 cm³.
Next, we shall determine the mass of the silver. This can be obtained as follow:
Density (D) of silver = 10.5 g/cm³
Volume of the silver = 830584 cm³.
Mass of silver =.?
Density = mass /
10.5 = mass of silver /830584
Cross multiply
Mass of silver = 10.5 × 830584
Mass of silver = 8721132 g
Finally, we shall convert the mass of silver, 8721132 g to kilogram (kg). This can be obtained as follow:
1000 g = 1 Kg
Therefore,
8721132 g = 8721132 g / 1000 g × 1 Kg
8721132 g = 8721.132 Kg
Therefore, the mass of each cube of silver is 8721.132 Kg
