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Delicious77 [7]
3 years ago
10

If you drop an object from rest, the distance it falls is given by (1/2)at2, where a is the acceleration of the object and t is

the amount of time fallen. Suppose you drop an object and measure the distance it falls. Suppose you drop it again, but it falls for three times the amount of time as before. How far did it fall on the second drop?
Select one:
a. It will fall twice the distance compared to the first time dropped.
b. It will fall three times the distance compared to the first time dropped.
c. It will fall nine times the distance compared to the first time dropped.
d. It depends on the planet you are on when you drop it.
Physics
1 answer:
klio [65]3 years ago
7 0

If,

d \:  =  \:   \frac{1}{2} a {t}^{2}

then, with 3x time t, (suppose, new distance is h)

h \:  =  \:   \frac{1}{2} a {(3t)}^{2}

=  \frac{1}{2} a9 {t}^{2}

= 9 \:  \frac{1}{2} a{t}^{2}

= 9d

Therefore, new distance h will be 9 times bigger than distance d.

answer: c

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Read 2 more answers
While driving north at 25 m/s during a rainstorm you notice that the rain makes an angle of 38° with the vertical. While driving
Natali [406]

Answer:21.33^{\circ}

Explanation:

Given

velocity of driver v_1=25 m/s w.r.t ground towards north

driver observes that rain is making an angle of 38^{\circ} with vertical

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suppose u_1=velocity of rain drop relative car while car is going towards north

u_2=velocity of rain drop relative car while car is going towards south

z=vector sum of u_1 & v_1

Now from graph

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z=\vec{u_2}+\vec{v_2}

therefore magnitude of z is given by

|z|=\sqrt{u_2^2+v_2^2}

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\tan A=\frac{v_2}{u_2}

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A=21.33^{\circ}

Thus rain drops make an angle of 21.33^{\circ} w.r.t to ground

6 0
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