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3 years ago

A force of 10 N making an angle 30 with horizontal .its horizontal component wll be

Physics

1 answer:

Norma-Jean [14]3 years ago

7 0

Answer:

10 cos (30)N

Explanation:

So, if we were to visualize it for a sec

we would see 10 as the hypotenuse, 30 as the angle between and would be solving for the adjacent side

So, using basic trig rules,

using the fact that cos(30)=x/10

x=10 cos (30)N

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Answer:

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3 years ago

The equation of a transverse wave traveling along a string is 1 1 y (2.00 mm)sin[(20 m )x (600 s )t] − − = − Find the (a) amplit

Lelu [443]

Answer:

a)Amplitude ,A = 2 mm

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d) λ = 0.31 m

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Explanation:

Given that

$y=2\ mm\ sin[(20m^{-1})x-(600s^{-1})t]$

As we know that standard form of wave equation given as

$y=A sin(\phi -\omega t)$

A= Amplitude

ω=Frequency (rad /s)

t=Time

Φ = Phase difference

$y=2\ mm\ sin[(20m^{-1})x-(600s^{-1})t]$

So from above equation we can say that

Amplitude ,A = 2 mm

Frequency ,ω= 600 rad/s (2πf=ω)

ω= 2πf

f= ω /2π

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K= 20 rad/m

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V= ω /K

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V = f λ

30 = 95.49 x λ

λ = 0.31 m

We know that speed is the rate of displacement

$U=\dfrac{dy}{dt}$

$U=2\ mm\ sin[(20m^{-1})x-(600s^{-1})t]$

$U=1200\ cos[(20m^{-1})x-(600s^{-1})t]\ mm/s$

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4 years ago

If a cannonball is fired horizontally it will not go in a straight line why?

goldfiish [28.3K]

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2 years ago

A force of 10 N making an angle 30 with horizontal .its horizontal component wll be​

A force of 10 N making an angle 30 with horizontal .its horizontal component wll be