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When the object is at the focal point the angular magnification is 2.94.
Angular magnification:
The ratio of the angle subtended at the eye by the image formed by an optical instrument to that subtended at the eye by the object when not viewed through the instrument.
Here we have to find the angular magnification when the object is at the focal point.
Focal length = 6.00 cm
Formula to calculate angular magnification:
Angular magnification = 25/f
= 25/ 8.5
= 2.94
Therefore the angular magnification of this thin lens is 2.94
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We know that:
d=vt
d=32mph*5h
d=160mi
Answer:
The answer is C 1.8V and 0.38A
Answer:
Explanation:
To solve this exercise it is necessary to take into account the concepts related to gravitational potential energy, as well as the concept of perigee and apogee of a celestial body.
By conservation of energy we know that,
Where,
Replacing
Our values are given by,
Replacing at the equation,
Therefore the Energy necessary for Sputnik I as it moved from apogee to perigee was
