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4 years ago

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Speed limit signs are placed every 58 mi on the highway. How many signs are there on a 75 mi stretch of highway? Which operation

should be used to solve the problem? division multiplication

1 answer:

ki77a [65]4 years ago

5 0

Answer:

you should use multiatication

Step-by-step explanation:

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A triangle has side lengths of 5a +3 inches and 2a +3 inches. If the perimeter of the triangle is 3a + 12 inches, which expressi

JulsSmile [24]

Answer:

A. 2a+6

Step-by-step explanation:

I did the test and this is what I got.

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3 years ago

An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is n

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4 years ago

Read 2 more answers

Alla and balla together drink 750ML of water. Of alla drinks 50% more than balla how much does Alla drink

Akimi4 [234]

Answer:

450 ml.

Step-by-step explanation:

Let x be the amount of water drank by Alla and y be the amount of water drank by Balla.

We have been given that Alla and Balla together drink 750 ML of water. We can represent this information as:

$x+y=750...(1)$

We are also told that Alla drinks 50% more than Balla. We can represent this information as:

$x=1.5y...(2)$

From equation (1) we will get,

$y=750-x$

Upon substituting this value in equation (2) we will get,

$x=1.5(750-x)$

Upon distributing 1.5 to right hand side of the equation we will get,

$x=1125-1.5x$

Upon adding 1.5x to both sides of equation we will get,

$x+1.5x=1125-1.5x+1.5x$

$2.5x=1125$

Let us divide both sides of our equation by 2.5.

$\frac{2.5x}{2.5}=\frac{1125}{2.5}$

$x=450$

Therefore, Alla drank 450 ml of water.

8 0

3 years ago

1. What is the equation for the Standard Form of a Line?

likoan [24]

Answer: Hi there

Standard Form: the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers. The standard form of a line is just another way of writing the equation of a line.

Brainliest?

:D

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3 years ago

A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January

Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that $p = 0.23$

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109$

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116$

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

$E(X) = np = 10*0.23 = 2.3$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33$

The expected number is 2.3 and the standard deviation is 1.33.

5 0

3 years ago