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3 years ago

How often does the moon go through an entire set of phases

Physics

1 answer:

kirza4 [7]3 years ago

5 0

Answer: About 29.5 days.

Explanation: It takes 27 days, 7 hours, and 43 minutes for our Moon to complete one full orbit around Earth. This is called the sidereal month, and is measured by our Moon's position relative to distant “fixed” stars. However, it takes our Moon about 29.5 days to complete one cycle of phases (from new Moon to new Moon).

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To make and sell fireplaces, Hearth, Inc., buys igniters, tubing, and other parts from Inflame Parts and installs them without m

skelet666 [1.2K]

Answer:

Infrared Wavelength

Explanation:

It is because the most long range wavelength i n this case will be the infrared wavelength that has a heating effect on bodies when exposed for a longer period of times. Similarly, the visible wavelength of light is also involved. The defective parts in the fireplace will allow the escape of these infrared wavelength radiations. This heating effect can cause fire near the fire place where the defective fireplace is placed without modifications.

3 0

3 years ago

Which of the following best describes a longitudinal wave?

Misha Larkins [42]

Answer:

A part not for sureokay

6 0

3 years ago

What is the magnetic field strength, in units of microTesla (T), at a distance of 6.3 cm from a long straight wire carrying a cu

bezimeni [28]

Answer:

$2.1 \mu T$

Explanation:

The magnetic field strength is given by:

$B=\frac{\mu_0 I}{2 \pi r}$

where

$\mu_0$ is the vacuum permeability

I is the current

r is the distance from the wire

In this problem,

I = 6.5 A

r = 6.3 cm = 0.063 m

So, the magnetic field strength is

$B=\frac{(1.256\cdot 10^{-7} H/m)(6.5 A)}{2 \pi (0.063 m)}=2.1\cdot 10^{-6} T=2.1 \mu T$

7 0

3 years ago

The action of two forces. One is a forward force of 1157 N provided by traction between the wheels and the road. The other is a

Pie

Complete question

A 2700 kg car accelerates from rest under the action of two forces. one is a forward force of 1157 newtons provided by traction between the wheels and the road. the other is a 902 newton resistive force due to various frictional forces. how far must the car travel for its speed to reach 3.6 meters per second? answer in units of meters.

Answer:

The car must travel 68.94 meters.

Explanation:

First, we are going to find the acceleration of the car using Newton's second Law:

$\sum\overrightarrow{F}=m\overrightarrow{a}$ (1)

with m the mass , a the acceleration and $\sum\overrightarrow{F}$ the net force forces that is:

$(F-f)$ (2)

with F the force provided by traction and f the resistive force:

(2) on (1):

$(F-f)=ma$

solving for a:

$a=\frac{F-f}{m} =\frac{1157N-902N}{2700kg} =0.094\frac{m}{s^{2}}$

Now let's use the Galileo’s kinematic equation

$Vf^{2}=Vo^{2}+2a\varDelta x$ (3)

With Vo te initial velocity that's zero because it started from rest, Vf the final velocity (3.6) and $\varDelta x$ the time took to achieve that velocity, solving (3) for $\varDelta x$ :