Momentum = (mass) x (speed)
Momentum = (8 kg) x (5 m/s)
Momentum = 40 kg-m/s
Answer:8.28 km
Explanation:
Given
First it drifts
2.5 km

Secondly it drifts
4.70 km

After that it drifted along east direction 5.1 km

After that it drifts
7.2 km

After that it drifts
2.8 km

=
+![\left [ 2.5sin45-4.7sin60-7.2sin55+2.8sin5\right ]\hat{j}](https://tex.z-dn.net/?f=%5Cleft%20%5B%202.5sin45-4.7sin60-7.2sin55%2B2.8sin5%5Cright%20%5D%5Chat%7Bj%7D)


for direction

south of east
Answer:
1411.8 N/m
Explanation:
From Hooke's law;
F= Ke
Where
F= force on the spring
K= force constant
e = extension
But e= 8.50 × 10^-2m
F= weight = 12.0 kg × 10 = 120 N
K = F/e = 120/8.50 × 10^-2
K= 1411.8 N/m
Answer:
22m/s
Explanation:
lowest part on the graph (closest to x-axis)
You are given the mass of a sphere that is 26 kg sphere and it is released from rest when θ = 0°. You are also given the force of the spring that is F = 100 N. You are asked to find the tension of the spring. Imagine that the sphere is connected to a spring. The spring exerts a tension and the spring exerts gravitational pull. This will follow the second law of newton.
T - F = ma
T = ma + F
T = 26kg (9.81m/s²) + 100 N
T = 355.06 N