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mojhsa [17]
2 years ago
6

If you stretch a rubber hose and pluck it, you can observe a pulse traveling up and down the hose.(i) What happens to the speed

of the pulse if you stretch the hose more tightly?(a) It increases.(b) It decreases.(c) It is constant.(d) It changes unpredictably.
Physics
1 answer:
Monica [59]2 years ago
4 0

The thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

<h3>What is wage speed?</h3>

It should be noted that wave speed simply means the distance that a wave travels during a particular time.

It should be noted that higher tension leads to an increase in the speed of the wave.

Therefore, the thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

Learn more about speed on:

brainly.com/question/13943409

#SPJ4

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Un depósito de gran superficie se llena de agua hasta una altura de 0,3 m. En el fondo del depósito hay un orificio de 5 cm2 de
ahrayia [7]

Answer:

a) El caudal de salida del chorro es 1.213\times 10^{-3}\,\frac{m^{3}}{s}.

Explanation:

a) Asúmase que el tanque se encuentra a presión atmósferica y que la sima del tanque tiene una altura de 0 metros. La rapidez de salida del chorro del depósito se determined a partir del Principio de Bernoulli, cuya línea de corriente entre la cima y la sima del tanque queda descrita por la siguiente ecuación:

\Delta z = \frac{v_{out}^{2}}{2\cdot g}

Donde:

\Delta z - Diferencia de altura, medida en metros.

g - Constante gravitacional, medida en metros por segundo al cuadrado.

v_{out} - Rapidez de salida del chorro, medida en metros por segundo.

Se despeja la rapidez de salida del chorro:

v_{out} = \sqrt{2\cdot g \cdot \Delta z}

Si g = 9.807\,\frac{m}{s^{2}} y \Delta z = 0.3\,m, entonces la rapidez de salida del chorro es:

v_{out} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.3\,m)}

v_{out} \approx 2.426\,\frac{m}{s}

Ahora, la cantidad de líquido que sale del depósito por unidad de tiempo se obtiene al multiplicar la rapidez de salida del chorro por el área transversal del orificio. Esto es:

\dot V_{out} = v_{out}\cdot A_{t}

Donde:

v_{out} - Rapidez de salida del chorro, medida en metros por segundo.

A_{t} - Área transversal del orificio, medido en metros cuadrados.

\dot V_{out} - Caudal de salida del chorro, medido en metros cúbicos por segundo.

Dado que v_{out} = 2.426\,\frac{m}{s} y A_{t} = 5\,cm^{2}, el caudal de salida del chorro es:

\dot V_{out} = \left(2.426\,\frac{m}{s} \right)\cdot (5\,cm^{2})\cdot \left(\frac{1}{10000}\,\frac{m^{2}}{cm^{2}}  \right)

\dot V_{out} = 1.213\times 10^{-3}\,\frac{m^{3}}{s}

El caudal de salida del chorro es 1.213\times 10^{-3}\,\frac{m^{3}}{s}.

5 0
3 years ago
Mr. Llama walked from his house to the bus stop. The bus stop is 2 miles from his house. He returned back to his house from the
Hoochie [10]

Answer:

Displacement of Mr. Llama: Option D. 0 miles.

Explanation:

The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.

For Mr. Llama:

  • Final position: Mr. Llama's house;
  • Initial position: Mr. Llama's house.

The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.

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What causes plastic flow to occur?
FinnZ [79.3K]
The answer to this is c. High pressure causes plastic flow to occur.
7 0
3 years ago
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Natalka [10]

Answer:

1.4 s

Explanation:

Given the following data;

Quantity of charge, Q = 2.5 C

Current = 1.8 A

To find the time required;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge, Q = current * time

Substituting into the formula, we have;

2.5 = 1.8 * time

Time = 2.5/1.8

Time = 1.4 s

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Answer:

The Curiosity rover found that ancient Mars had the right chemistry to support living microbes. Curiosity found sulfur, nitrogen, oxygen, phosphorus and carbon-- key ingredients necessary for life--in the powder sample drilled from the "Sheepbed" mudstone in Yellowknife Bay.

Explanation:

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