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LiRa [457]
3 years ago
9

A certain type of D-cell battery that costs $0.50 is capable of producing 1.3 V and a current of 0.3 A for a period of 75 hours.

Determine the cost of the energy delivered by this battery per kilowatt hour. (For comparison, the approximate cost of energy purchased from electric utilities in the United States is $0.12 per kilowatt hour.)
Physics
1 answer:
Arte-miy333 [17]3 years ago
6 0

Answer:

$3.51

Explanation:

The energy (E) delivered by a system is the product of the power (P) dissipated by the system and the time (t) taken for the dissipation. i.e

E = P x t -----------------------(i)

Where;

The power (P) is the product of the current (I) flowing through the system and the voltage (V) across the system. i.e

P = I x V

Substituting P = I x V into equation (i) gives;

E = (I x V) x t

=> E = IVt    --------------------(ii)

<em>From the question;</em>

Current (I) = 0.3A

Voltage (V) = 1.3V

time (t) = 75 hours = 75h

<em>Substituting these values into equation (ii) gives;</em>

=> E = 0.3 x 1.3 x 75

=> E = 29.25 Kwh

The energy delivered is 29.25Kwh

But in the U.S;

$0.12 = 1Kwh

=> 29.25Kwh = 29.25 x $0.12

=> $3.51

Therefore, the cost of the energy delivered by this battery per kilowatt hour is $3.51

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(a) The distance of the image formed by the concave mirror is 19.1 cm.

(b) The image formed is diminished and real.

<h3>Image distance </h3>

The distance of the image formed by the concave mirror is calculated as follows;

1/f = 1/v + 1/u

1/v = 1/f - 1/u

1/v = 1/15 - 1/70

1/v = 0.05238

v = 1/0.05238

v = 19.1 cm

The image distance is smaller than object distance, thus the image formed is diminished and real.

Learn more about concave mirror here: brainly.com/question/13164847

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which of the following types of exercise increase lean body mass?. A.) cardiorespiratory fitness. B.) flexibility. C.) muscular
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A lean body mass that the cholesterol level in the body is low and that the excess fats in the body are getting rid off as much as one can. In this case, the exercises  A.) cardiorespiratory fitness such as jogging and <span>C.) muscular strength and endurance such as body building, abs routines are employed. Answer is D. both A and C.</span>
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3 years ago
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Suppose a wheel with a tire mounted on it is rotating at the constant rate of 2.83 times a second. A tack is stuck in the tire a
timama [110]

Answer:

The tangential speed of the tack is 6.988 meters per second.

Explanation:

The tangential speed experimented by the tack (v), measured in meters per second, is equal to the product of the angular speed of the wheel (\omega), measured in radians per second, and the distance of the tack respect to the rotation axis (R), measured in meters, length that coincides with the radius of the tire. First, we convert the angular speed of the wheel from revolutions per second to radians per second:

\omega = 2.83\,\frac{rev}{s} \times \frac{2\pi\,rad}{1\,rev}

\omega \approx 17.781\,\frac{rad}{s}

Then, the tangential speed of the tack is: (\omega \approx 17.781\,\frac{rad}{s}, R = 0.393\,m)

v = \left(17.781\,\frac{rad}{s} \right)\cdot (0.393\,m)

v = 6.988\,\frac{m}{s}

The tangential speed of the tack is 6.988 meters per second.

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The aurora is caused when electrons and protons, moving in the earth’s magnetic field of ≈5.0×10−5t, collide with molecules of t
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The question is incomplete. I can help you by adding the information missing. They want you to calculate a) the radius of the cyclotron orbit for an electron with speed 1.0 * 10^6 m/s^2 and b) the radius of a cyclotron orbit for a proton with speed 5.0 * 10^4 m/s.

The two tasks involve combining the equations of the magnectic force and the centripetal force in a circular motion.

When you do that, you will obtain an expression to find the radius of the circular motion, which is the radius of the cyclotron that impulses the particles.

a)

Magentic force, F = q*v*B

q is the charge of the electron = 1.6 * 10^ -19 C
v is the speed = 1.0 * 10 ^ 6 m/s
B is the magentic field = 5.0 * 10 ^-5 T

Centripetal force, F = m*Ac = m * v^2 / R

where,

Ac = centripetal acceleration
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R = the radius of the orbit

Now equal the two forces: q*v*B = m * v^2 / R => R =  m*v / (q*B)

=> R = (9.11 * 10^31 kg) (1.0*10^6m/s) / [ (1.6 * 10^-19C)* (5.0 * 10^-5T) ]

=> R = 0.114 m

b) The equations are the same, just now use the speed, charge and mass of the proton instead of those of the electron.

R = m*v / (qB) = (1.66*10^-27 kg)(5.0*10^4 m/s) / [(1.6*10^-19C)(5*10^-5T)]

=> R = 10.4 m

 

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3 years ago
Suppose a=3i-2j+k b=-i-4j+3k and c is avector lying along positive x axis with the property that a(b+c)=0 then find c?
il63 [147K]

The value of the c will be (0 i+0 j+0 k). c is a vector that is along the positive x-axis and has the condition a(b+c)=0.

<h3>What is a vector?</h3>

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

Given ;

a=3i-2j+k

b=-i-4j+3k

Given property:

a(b+c)=0

-i-4j+3k ((-i-4j+3k)+c)=0

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14(-i-4j+3k)c=0

c=0 i+0 j+0 k

Hence, the value of the c will be (0 i+0 j+0 k).

To learn more about the vector refer to the link;

brainly.com/question/13322477

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6 0
1 year ago
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