First calculate number of Nitrogen atoms contained by 1 mole of Zn(NO₃)₂,
As one formula unit of Zn(NO₃)₂ contains 2 Nitrogen atoms, then one mole of Zn(NO₃)₂ will contain,
= 2 × 6.022 × 10²³
= 1.20 × 10²⁴ Atoms of Nitrogen / mole
Now, calculate number of Nitrogen Atoms in 0.150 moles of Zn(NO₃)₂.
As,
1 mole of Zn(NO₃)₂ contained = 1.20 × 10²⁴ atoms of N
Then,
0.15 mole of Zn(NO₃)₂ will contain = X atoms of N
Solving for X,
X = (0.15 mol × 1.20 × 10²⁴ atom) ÷ 1 mol
X = 1.80 × 10²⁴ Atoms of Nitrogen
Result:
So, 0.15 mole of Zn(NO₃)₂ contains 1.80 × 10²⁴ atoms of Nitrogen.
Answer:
m = 859.5 g
Explanation:
d (Uranium) = 19.1 g/cm3
V = 45 cm3
m = V × d = 45 × 19.1 = 859.5 g
Answer:
I think it might be a closed system
