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Goryan [66]
2 years ago
15

a ball of mass 0.80 kg moving at a speed of 2.5 m/s along a straight line collided with a mass 2.5 kg which was initially statio

nary. As a result of the collision, the 2.5 g ball was given a velocity of 1.0 m/s along the same line. Calculate the speed and irection of the 0.80 kg ball immediately after the collision.​
Physics
1 answer:
Likurg_2 [28]2 years ago
5 0

The speed of the 0.8 kg ball immediately after collision is 0.625 m/s in opposite direction to the stationary ball.

The given parameters;

  • mass of the ball, m₁ = 0.8 kg
  • speed of the ball, u₁ = 2.5 m/s
  • mass of the object at rest, m₂ = 2.5 kg
  • final velocity of the object at rest, v₂ = 1 m/s

Let the final velocity of the 0.8 kg ball immediately after collision = v₁

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

(0.8 x 2.5) + (2.5 x 0) = (0.8)v₁  +  2.5(1)

2 = 2.5 + (0.8)v₁

-0.5 = (0.8)v₁

v_1 = \frac{-0.5}{0.8} \\\\v_1 = -0.625 \ m/s

Thus, the speed of the 0.8 kg ball immediately after collision is 0.625 m/s in opposite direction to the stationary ball.

Learn more here: brainly.com/question/7694106

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Find the current passing through a circuit consisting of a battery and one resistor. The resistance has a retance of 2ohms and t
Bingel [31]

The current passing through a circuit consisting of a battery of 12 V and resistor of 2 ohms is 6 Ampere .

Explanation:

  • Assume the wires are ideal with zero resistance.  
  • The current passing through the circuit will be  

           I = V/R = 12/2 = 6.000 A.

5 0
3 years ago
A 5.5-kW resistance heater in a water heater runs for 3 hours to raise the water temperature to the desired level. Determine the
Stella [2.4K]

Answer:

16.5 kwh and 59400 kJ.

Explanation:

kWh is a measure of energy that is equivalent to the power in kw times the number of hours the device worked.

In this case, it would be equal to:

E_{kwh}=5.5kw*3h=16.5kwh

1 kw also means 1kj of energy spent per second. With this, we calculate the amount of energy in kJ spent by the resistance:

E_{kJ}=5.5\frac{kJ}{s}*3h*\frac{3600s}{1h} = 59400 kJ

5 0
3 years ago
If the velocity of a car is 45 km/h west, how far can it travel in 0.5 hours?
Anarel [89]
45km/h * 0.5h= 22.5km

The car can travel 22.5km in 0.5 hours
6 0
2 years ago
Read 2 more answers
How much does the earth/sky weigh?
Talja [164]
Calculated weight (by experimentally) of Earth is 5.972 × 10²⁴ N

Hope this helps!
6 0
2 years ago
1) A force of 157 N is applied to a box 25o above the horizontal. If it is applied over a distance of 14.5 m how much work is do
vfiekz [6]

#1

Work done is given by

W = F.d cos\theta

here we know that

F = 157 N

d = 14.5

\theta = 25^0

now from the above formula

W = (157)(14.5)cos25 = 2063.2 J

#2

By energy conservation

Initial total potential energy of egg = final total kinetic energy of egg

mgh = \frac{1}{2}mv^2

v = \sqrt{2gh}

v = \sqrt{2(9.8)(8.2)}

v = 12.7 m/s

#3

By momentum conservation we know that

m_1v_1 = (m_1 + m_2)v

215(9.5) = (215 + 19.7) v

v = \frac{215 (9.5)}{215 + 19.7}

v = 8.7 m/s

#4

by momentum conservation we know that

m_1v_1 + m_2v_2 = (m_1 + m_2) v

let direction of velocity of Jay Z car motion is positive direction

now we will say

1100(-20) + 1475v = (1100 + 1475)(7)

1475 v = 2575(7) + 1100(20)

v = 27.14 m/s

Yes Jay Z is overspeeding as his speed is more than speed limit

#5

Tension force in the string will be centripetal force

so here we can say

T = \frac{mv^2}{R}

here we know that

m = 0.63 kg

v = 7.8 m/s

R = 0.23 m

T = \frac{0.63 (7.8)^2}{0.23}

T = 166.6 N

6 0
3 years ago
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