Answer:
the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.
Explanation:
Let the spring constant of the spring is k.
For clown A:
m = 40 kg
let the extension in the spring is y.
So, the spring force, F = k y
m g = k y
40 x g = k x y
y = 40 x g / k ..... (1)
For clown B:
m' = 60 kg
Let the extension in the spring is y'.
So, the spring force, F' = k y'
m' g = k y'
y' = 60 x g / k .....(2)
Kinetic energy for A, K = 1/2 ky^2
Kinetic energy for B, K' = 1/2 ky'^2
So, K/K' = y^2/y'^2 K / K' = (40 x 40) / (60 x 60) (from equation (1) and (2))
K / K' = 0.444
K = 0.444 K'
So the kinetic energy of clown A is 0.444 times the kinetic energy of clown B.
Answer:
Explanation:
According to the <u>Third Kepler’s Law</u> of Planetary motion:
(1)
Where;:
is the period of the satellite
is the Gravitational Constant and its value is
is the mass of the Earth
is the semimajor axis of the orbit the satllite describes around the Earth (as we know it is a circular orbit, the semimajor axis is equal to the radius of the orbit).
On the other hand, the orbital velocity is given by:
(2)
Now, from (1) we can find
, in order to substitute this value in (2):
(3)
(4)
(5)
Substituting (5) in (2):
(6)
(7) This is the speed at which the satellite travels
Answer:
They are both mechanical waves
Answer:
0.75kg into gram = 0.75 * 1000 = 750g
potential energy = mgh
potential energy = 750 * 10 * 0.35
potential energy = 2625 joules
Answer:
750cm³
Explanation:
volume = length × width × height
15 × 10 × 5 = 750
750cm³