Answer:
q = 0.42
Explanation:
This question is an example of Hardy-Weinberg question and there are two equations necessary to carry out this question;
p + q = 1
p² + 2pq + q² = 1
where;
p = the frequency of the dominant allele
q = the frequency of the recessive allele
p² = the frequency of individuals with homozygous dominant genotype
2pq = the frequency of individuals with heterozygous genotype
q² = frequency of individuals with the homozygous recessive genotype
Since the total population = 425
q² = 
= 
q² = 0.1765
To find q; we need to square root both side to eliminate the square from q².
∴
q = 0.4201
q = 0.42 (to two decimal places)
Answer:
The two major pancreatic enzymes that digest proteins in the small intestine are chymotrypsin and trypsin. Trypsin activates other protein-digesting enzymes called proteases, and together, these enzymes break proteins down to tripeptides, dipeptides, and individual amino acids.
Answer:
The answer is B: The child will likely have Tay-Sachs disease if both parents pass on the dominant alleles.
Explanation:
Brainliest pls!!