1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phoenix [80]
3 years ago
11

An airplane started at a distance of 20 km from Chicago and flew directly

Physics
1 answer:
Alisiya [41]3 years ago
7 0

Answer:

C 35 km , is the answer

Explanation:

d=55 - 20 = 35

You might be interested in
What is the purpose of the zigzag line on the periodic table
OverLord2011 [107]
<span>It separates the metals from the non metals</span>
5 0
3 years ago
Read 2 more answers
A toy airplane, flying in a horizontal, circular
Goshia [24]

Answer:

8.4 m/s

Explanation:

The toy completes 10 circle in 30 seconds. So its frequency of revolution is

f=\frac{10}{30 s}=0.33 Hz

The periof of revolution is the reciprocal of the frequency, so

T=\frac{1}{f}=\frac{1}{0.33 Hz}=3 s

The radius of the circular path is

r = 4.0 m

So the total distance covered by the toy in one circle is the length of the circumference:

2\pi r

And so the average speed is

v=\frac{2\pi r}{T}=\frac{2\pi (4.0 m)}{3 s}=8.4 m/s

4 0
3 years ago
Read 2 more answers
Charge is placed on two conducting spheres that are very far apart and connected by a long thin wire. The radius of the smaller
mrs_skeptik [129]

Answer:

surface charge density on each sphere is 440 \times 10^{-9} C

Explanation:

given data

radius of smaller sphere = 5 cm

radius of  larger sphere is 12 cm

electric field at surface of larger sphere = 660 kV/m = 660 × 1000 v/m

solution

we apply here electric field formula that is express as

E = (\frac{1}{4\pi\epsilon  })\times  (\frac{Q_{1} }{R^{2} } )    .................1

put here value

660000 = 9 \times 10^9 \times \frac{Q1}{0.12^2}  

Q1 = 1056 × 10^{-9}

and

here field inside a conductor is zero so that electric potential ( V ) is constant

\frac{Q{1} }{R} = \frac{Q{2} }{r}   ..................2

so Q2 will be

Q2 =  \frac{5}{12} \times 1056 \times 10^{-9}  

Q2 =  440 \times 10^{-9}  C

6 0
3 years ago
Describe the kinetic molecular theory
tatuchka [14]
The kinetic theory of gases is a simple, historically significant model of the thermodynamic behavior of gases, with which many principal concepts of thermodynamics were established. The model describes a gas as a large number of identical submicroscopic particles, all of which are in constant, rapid, random motion
8 0
3 years ago
A body having uniform velocity has zero acceleration? give reason​
Sonja [21]

Answer:

A body having uniform velocity has zero acceleration because

there is not change in velocity.

5 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE HELP!!
    7·2 answers
  • A machine has an efficiency of 80% how much work must be done on the machine so to make it do 50000 J of outfit work
    6·1 answer
  • How many electrons does nitrogen (N) need to gain to have a stable outer electron shell?
    14·1 answer
  • hen a series combination of two capacitors is connected to a 12 V battery, 173 of energy is drawn from the battery. If one of th
    9·2 answers
  • A 2-kg object is initially at the bottom of a long 50° inclined plane, and is beginning to slide up this inclined plane. The ini
    9·1 answer
  • A 110. g wooden block is initially at rest on a rough horizontal surface when a 12.8 g bullet is fired horizontally into (but do
    10·1 answer
  • If the particle is located slightly to the left of point B, its acceleration is __________.
    8·1 answer
  • On a distant planet, golf is just as popular as it is on earth. A golfer tees off and drives the ball 2.50 times as far as he wo
    13·1 answer
  • If a Ball Falls from a girls hand, How does its speed change?
    6·2 answers
  • Suppose you needed to push a 1,500-N sofa up a frictionless ramp with a 30° angle. How much force would you have to apply to the
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!