Answer:
okay lol, ima use this for points if okay
Explanation:
Answer:
78.85
Explanation:
To <u>calculate the average atomic mass of the isotopes </u>we use the <em>given masses and abundances</em>, as follows:
- Mass of Isotope 1 * Abundance of Isotope 1 + Mass of Isotope 2 * Abundance of Isotope 2 + ....
In other words:
- 78 amu * 75/100 + 81 amu * 15/100 + 82 amu * 10/100 = 78.85
So the answer is 78.85.
Answer:
.500
Explanation:
Use the ideal gas law equation: PV = nRT
Plug in the initial values given:
P = 1.2 atm
V = .500 L
n = number of moles
R = Gas Constant 8.314
T = 25.0 C
(1.2)(.5) = n(8.314)(25)
solving for n we get .00289
Now use the same equation with the new values solving for V
(3.6)V = (.00289)(8.314)(75.0)
V = .4999999 ROund to .500