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oee [108]
3 years ago
10

Please help me!!!!! I REALLY NEED HELP!!! What is my carbon footprint and how can I reduce it?

Chemistry
2 answers:
vitfil [10]3 years ago
7 0

Answer:

your carbon footprint is how often you use a car of vehical you can decreese it by riding a bike or walking.

Explanation:

Y_Kistochka [10]3 years ago
4 0

Carbon footprint is like when you ride a car and it produces lots of carbon monoxide in the air. Ways to reduce it is by walking, riding a bicycle or using the bus for transportation. Hope this helps.

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What is the charge on an electron? <br><br> -1<br> 0<br> +1<br> -2
Mama L [17]

An electron has a negative charge of one

An neutron has no charge (hence, neutral)

An proton has a positive charge of one

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5 0
4 years ago
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Why does the earth rotate
boyakko [2]

Answer:

A

Explanation:

Your answer would be A because Earth is formed from cold gases collapsing due to gravity. The Solar System was formed when a huge amount of dust and gas began to collapse under its own gravity, and as the cloud collapse it started to spin causing the material within the cloud to gather into a swirl and then formed into planets and as the planets are formed they kept this spinning motion.

4 0
3 years ago
If there are three methyl groups on the same carbon, what is the prefix<br> used?
Tanzania [10]

Answer:

tri

Explanation:

1-nothing

2-di

3-tri

- Hope that helps! Please let me know if you need further explanation.

6 0
3 years ago
Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH
sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?

The intermediate balanced chemical reaction will be,

C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole..[1]

H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole..[2]

CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole [3]

The expression for enthalpy of formation of C_2H_4 will be,

\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0
3 years ago
Select the reason why two molecules of benzaldehyde cannot react via the aldol condensation.
Lesechka [4]
Benzaldehyde or C6H5CHO would not undergo the aldol condensation because it does not contain an alpha-hydrogen in its structure. Aldol condensation is a type of reaction that happens between an enolate and an aldehyde or ketone leading to a alkene that has a planar structure. The lack of an alpha-hydrogen would not allow for it to undergo such process since it cannot enolize. Benzaldehyde undergoes a nucleophilic reaction known as Claisen-Schmidt condensation. It has somehow same mechanism of the aldol reaction however, the nucleophilic attack on the carbonyl happens even without the alpha-hydrogen but with an enolate that is from a ketone.
4 0
3 years ago
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