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oee [108]
3 years ago
10

Please help me!!!!! I REALLY NEED HELP!!! What is my carbon footprint and how can I reduce it?

Chemistry
2 answers:
vitfil [10]3 years ago
7 0

Answer:

your carbon footprint is how often you use a car of vehical you can decreese it by riding a bike or walking.

Explanation:

Y_Kistochka [10]3 years ago
4 0

Carbon footprint is like when you ride a car and it produces lots of carbon monoxide in the air. Ways to reduce it is by walking, riding a bicycle or using the bus for transportation. Hope this helps.

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If you need to extract a 50 ml aqueous solution with 50 ml of dichloromethane, what is the minimum size of a separatory funnel y
tatuchka [14]

The dichloromethane (DCM) has less density than water and also the polarity of water is much more than DCM. So the mixture of water and dichloromethane will always be a heterogeneous mixture. In the mixture dichloromethane will be always up of the water layer. The volume of the separatory funnel which contains the mixture of DCM and water must have to be more than the total volume of the liquids thus the volume of the funnel will be more than (50+50) = 100mL.

The caution have to consider during the separation are-

1. The separatory funnel have to shake well with lid and have to settle down for some times until the two liquid separated.

2. The lid should be open very slowly as the vapor pressure of DCM is more and it will float on the water.

3. After this the stopcock should be opened and slowly the water will come out first followed by DCM.      

7 0
3 years ago
What is the volume of 43.7 g of helium at stp?
tankabanditka [31]
Answer is: volume of helium is 244.72 liters.
m(He) = 43.7 g.
n(He) = m(He) ÷ M(He).
n(He) = 43.7 g ÷ 4 g/mol.
n(He) = 10.925 mol.
V(He) = n(He) · n(He).
V(He) = 10.925 mol · 22.4 L/mol.
V(He) = 244.72 L.
Vm - molar volume at STP.
n - amount of substance.
0 0
3 years ago
Read 2 more answers
Xg of U and 3.795 g of O combine to form 20.00 g of
Deffense [45]

The percent composition of Uranium in U308 = C. 81.03%

<h3>Further explanation</h3>

Given

X g of U

3.795 g of O

20.00 g of  U308

Required

The percent composition of Uranium

Solution

mass of Uranium in U308 :

= mass of U308 - mass of O

= 20 g - 3.795 g

= 16.205 g

The percent composition :

\tt \%U=\dfrac{mass~U}{mass~U308}\times 100\%

%U = (mass U/mass U308) x 100%

%U= (16.205/20) x 100%

%U = 81.025≈81.03

8 0
3 years ago
If the half-life of the pesticide is 12 years
Dima020 [189]
K = 0.058 yr (constant)

Fraction of the pesticide  = 36 years/12 = 3 half-lives   , so around 1/8 left

when 99.9 % decomposed, 0.1 % is left , so the fraction is 0.001. To reach this point, it will take around +/- 120 years





5 0
4 years ago
What type of map is this?
LenaWriter [7]

Answer:

Both a Geologic and Topographic map. So C. is the Answer.

Explanation:

5 0
3 years ago
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