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Daniel [21]
3 years ago
15

A crane lifts a 6.500 N weight 10 m in 180 seconds. What power is used?

Physics
1 answer:
Nostrana [21]3 years ago
8 0
Power is work over time.

P= \frac{W}{t}

We can solve for work by using F*d

W=F*d = (6.500N)(10m) = 65 J

Now solve for power:

P= \frac{(65J)}{180s} = 0.361W

P=0.361W
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A stone is thrown vertically upward with a speed of 24.0 ms. (a) How fast is it moving when it reaches a height of 13.0 m? (b) H
Katena32 [7]

Answer:

Question A: 17.92m/s

Question B: 0.6 seconds

Explanation:

Question A:

Initial velocity(u)=24m/s

Height(h)=13m

acceleration due to gravity(g)=9.8m/s^2

Final velocity=v

v^2=u^2-2xgxh

v^2=24^2-2x9.8x13

v^2=24x24-2x9.8x13

v^2=576-254.8

v^2=321.2

Take them square root of both sides

v=√(321.2)

v=17.92m/s

Question B:

velocity(v)=17.92m/s

Acceleration due to gravity(g)=9.8m/s^2

Initial velocity(u)=24m/s

Time=t

v=u-gxt

17.92=24-9.8xt

Collect like terms

9.8t=24-17.92

9.8t=6.08

Divide both sides by 9.8

9.8t/9.8=6.08/9.8

t=0.6 approximately

5 0
3 years ago
What is the value of ΔVBA=VB−VA if the charge on the plates is 1.00 x 10-9 C, the area of the plates is 2.00 m2 and the distanc
Murljashka [212]

Answer:

The Value is V_{AB} = 2.825V

Explanation:

The explanation is shown on the first  uploaded image

5 0
4 years ago
_____ is the frictional force needed to slow an object in motion
s2008m [1.1K]

Answer:

<u>Drag force</u> is the frictional force needed to slow an object in motion

Explanation:

8 0
3 years ago
Read 2 more answers
Two planets have masses 2 x 10^23 kg and 5 x 10^22 kg, and the distance between them is 3 x 10^16 m. Calculate the gravitational
xxTIMURxx [149]

Explanation:

given,

mass of one planet (m1)=2*10^23 kg

mass of another planet (m2)=5*10^22kg

distance between them(d)=3*10^16m

gravitational constant(G)=6.67*10^-11Nm^2kg^-2

gravitational force between them(F)=?

we know,

F=Gm1m2/d^2

or, F=6.67*10^-11*2*10^23*5*10^22/(3*10^16)^2

or, F=6.67*2*5*10^-11+23+22/3*3*10^32

or, F=66.7*10^34/9*10^32

or, F=7.41*10^34-32

•°• F=7.41*10^2

thus, the gravitational force between them is 7.14*10^2

3 0
3 years ago
What is the internal energy of 2.00 mol of diatomic hydrogen gas (H2) at 35°C?
djyliett [7]
As you mentioned, we will use <span>Equipartition Theorem.
</span><span>H2 has 5 degrees of freedom; 3 translations and 2 rotation
</span>Therefore:
Internal energy = (5/2) nRT
You just substitute in the equation with the values of R and T and calculate the internal energy as follows:
Internal energy = (5/2) x 2 x <span>8.314 x 308 = 32.0089 x 10^3 J</span>
4 0
3 years ago
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