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DerKrebs [107]
3 years ago
9

Radio waves transmitted through space at 3.00 ✕ 108 m/s by the Voyager spacecraft have a wavelength of 0.137 m. What is their fr

equency (in Hz)?
Physics
1 answer:
fredd [130]3 years ago
8 0

Answer:

Frequency, f=2.18\times 10^9\ Hz

Explanation:

We have,

Speed of radio waves is 3\times 10^8\ m/s

Wavelength of radio waves is \lambda=0.137\ m

It is required to find the frequency of the radio waves. The speed of a wave is given by :

v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.137}\\\\f=2.18\times 10^9\ Hz

So, the frequency of the radio wave is 2.18\times 10^9\ Hz.

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A bicycle has a momentum of 36 kg • m/s and a velocity of 4 m/s. What is the mass of the bicycle? 9 kg 32 kg 40 kg 144 kg
igomit [66]

Answer:

9 kg

Explanation:

Momentum is mass times velocity.

p = mv

36 kgm/s = m (4 m/s)

m = 9 kg

3 0
3 years ago
Read 2 more answers
A square loop of wire is carrying current in the counterclockwise direction. There is a horizontal uniform magnetic field pointi
Citrus2011 [14]

1. C) The net force on the loop is zero

Explanation:

The uniform magnetic field points to the right, while the current is counterclockwise. We must analyze the direction of the force on each side of the loop.

However, we notice that:

- the current in the upper and lower side of the loop is parallel/anti-parallel to the magnetic field, so the magnetic force on these sides is zero

- the current in the left side and right side of the loop is perpendicular to the magnetic field, however the direction of the current in the two sides is opposite, so the two forces will be opposite, and since their magnitude is equal (because the field is uniform), then the net force must be zero

2. (B) around the y axis

Explanation:

We already said that the magnetic force on the upper and lower side of the loop is zero. So let's analyze the direction of the force on the left and right side of the loop:

- Left side: the current is flowing downward, while the magnetic field points to the right. Using the right-hand rule:

-- Index finger: current (downward)

-- Middle finger: magnetic field (to the right)

-- Thumb: force (out of the screen, positive z-axis)

- Right side: the current is flowing upward, while the magnetic field points to the right. Using the right-hand rule:

-- Index finger: current (upward)

-- Middle finger: magnetic field (to the right)

-- Thumb: force (into the screen, negative z-axis)

---> this means that the loop of wire will rotate around the y-axis.

7 0
4 years ago
A copper wire of diameter 0.80 mm fails at an engineering stress = 248.2 MPa. Its ductility is measured as 75% reduction of area
Anvisha [2.4K]

Answer:

true stress = 992.8 MPA

true strain = 1.386

Explanation:

see the attached file

4 0
3 years ago
Which two technologies use the same range of radio wave frequencies? television broadcasting and AM radio broadcasting cell phon
Tju [1.3M]
Let us reject some answers. AM and FM radio waves do not interfere. Am are an orders of magnitude larger than FM waves. FM waves belong to microwaves, a subcategory of radiowaves while AM does not. Similarly, AM  and TV have not the same, because TV uses a subset of the frequencies used in FM. The correct answe is that CB radios and submarine communication happen at the same wavelengths/frequencies, namely low frequency radiowaves.
4 0
4 years ago
Read 2 more answers
Tourists covered 255 km for a 4-hour ride by car and a 7-hour ride by train. what is the speed of the train, if it is 5 km/h gre
LekaFEV [45]
The distance covered by car is equal to (assuming it is moving by uniform motion) the product between the car's speed and the time of the car ride, 4 h:
S_c = v_c t_c
where
v_c is the car's speed
t_c = 4 h is the duration of the car ride

Similarly, the distance covered by train is equal to the product between the train's speed and the duration of the train ride, 7 h:
S_t = v_t t_t

The total distance covered is S=255 km, which is the sum of the distances covered by car and train:
S=255 km = S_c + S_t
which becomes
255 = 4 v_c + 7 v_t (1)
we also know that the train speed is 5 km/h greater than the car's speed:
v_t = 5 + v_c (2)

If we put (2) into (1), we find
255 = 4v_c + 7(5+v_c)
and if we solve it, we find
v_c = 20 km/h
v_t = 25 km/h

So, the car speed is 20 km/h and the train speed is 25 km/h.

4 0
4 years ago
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