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3 years ago

5

Calcium hydroxide is titrated with nitric acid. What volume of 0.0200 M calcium hydroxide is required to neutralize 35.00 ml of

0.0500 M nitric acid?

1 answer:

gogolik [260]3 years ago

8 0

Answer:

43.75 ml

Explanation:

Given that the equation of the reaction is;

2HNO3(aq) + Ca(OH)2(aq) ---> Ca(NO3)2(aq) + 2 H20(l)

Concentration of acid CA= 0.05 M

Concentration of base CB = 0.02 M

Volume of acid VA = 35.00ml

Volume of base VB= ???

Number of moles of acid NA= 2

Number of moles of base NB=1

From

CAVA/CBVB= NA/NB

Making VB the subject of the formula;

VB= CAVANB/CBNA

VB= 0.05 × 35 × 1/ 0.02 × 2

VB=1.75 /0.04

VB= 43.75 ml

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1) A car is traveling down the interstate at 37.1 m/s. The driver sees a cop and quickly slows down. If the driver slows to 29.8

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1)

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3)

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$P=\frac{W}{t}$

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$t=\frac{W}{P}=\frac{1250}{267}=4.68 s$

4)

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$KE=\frac{1}{2}mv^2$

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v is its speed

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KE = 125.6 is its kinetic energy

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5)

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6)

During a collision, the total momentum of the system is always conserved before and after the collision. So we can write:

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8)

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$c=f\lambda$

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3 years ago

How many grams of ice at -13 deg C must be added to 711 grams of water that is initially at a temperature of 87 deg C to produce

Basile [38]

Answer:

The answer to your question is m = 4.7 kg

Explanation:

Data

Ice Water

mass = ? mass = 711 g

T₁ = -13°C T₁ = 87°C

T₂ = 10°C T₂ = 10°C

Ch = 2090 J/kg°K Cw = 4180 J/kg°K

Process

1.- Convert temperature to kelvin

T₁ = 273 + (-13) = 260°K

T₁ water = 87 + 273 = 360 °K

T₂ = 10 + 273 = 283°K

2.- Write the equation of interchange of heat

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- mwCw(T₂ - T₁) = miCi(T₂ - T₁)

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m = 228842.46/48070

-Result

m = 4.7 kg

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4 years ago