Answer:
The answer is V =delta U over q
Explanation:
Electric potential is defined as the magnitude of the electric field through the potential energy that a charge would have if placed at that point. Mathematically, the potential is defined with the following expression:
where:
V is the electric potential. Its unit is Julius by Coulomb (J/C).
Ep is the electric potential energy that has a charge
q is the charge
In the question Ep = ΔU
Using K.E=1/2MV^2
answer is 125joules
When the balanced force is applied on the ball It will roll away from the force.
<u>Explanation:</u>
- A ball lies on the floor in rest. If the balanced force is applied to
the ball, the force will push away.
- The forces would include gravity and the forces of air particles entering the ball from almost all directions.
- And the ground is exercising the force and shifting away from the impact.
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Gases are not ionized while plasma is.
The kinetic energy of the proton is 3.4 kev
1 kev = 1.602 × 10^-16 joules
therefore 3.4 kev is equivalent to;
3.4 × (1.602 ×10^-16)= 5.4468 × 10^-16 J
Kinetic energy is calculated by the formula 1/2mv² where m is the mass and v is the velocity.
Therefore V = √((2 × ( 5.4468×10^-16))/ (1.67 ×10^-27))
= 8.077 × 10^5 m/s
