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Bas_tet [7]
3 years ago
12

Write a balanced equation and indicate the reaction type (single or double replacement, decomposition, or composition/synthesis)

for each of the following:
Iron (III) bromide (aq) + ammonium sulfide (aq) --> iron (III) sulfide (s) + ammonium bromide (aq)
Calcium oxide (s) + diphosphorus pentoxide (s) --> calcium phosphate (s)
Magnesium chloride (aq) + silver nitrate (aq) --> magnesium nitrate (aq) + silver chloride (s)
Sodium carbonate (aq) + sulfuric acid (aq) --> sodium sulfate (aq) + carbon dioxide (g) + water (l)
Iron (II) sulfide (is) + hydrochloric acid (aq) --> iron (II) chloride (aq) + hydrogen sulfide (g)
Chemistry
1 answer:
bulgar [2K]3 years ago
3 0

<u>Answer:</u> The equations are written below.

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

AB+C\rightarrow CB+A

Element C is more reactive than element A.

Double displacement reaction is defined as the reaction in which exchange of ions takes place.

AB+CD\rightarrow CB+AD

Decomposition reaction is defined as the reaction in which a large substance breaks down into smaller substances.

AB\rightarrow A+B

Synthesis reaction is defined as the reaction in which smaller substances combine in their elemental state to form a larger substance.

A+B\rightarrow AB

For the given options:

  • <u>Option 1: </u>Iron (III) bromide reacting with ammonium sulfide to produce iron (III) sulfide and ammonium bromide

The balanced chemical equation follows:

Fe_2(SO_4)_3+3(NH_4)_2S\rightarrow Fe_2S_3+3(NH_4)_2SO_4

This is considered as double displacement reaction.

  • <u>Option 2:</u> Calcium oxide reacting with diphosphorus pentoxide to produce calcium phosphate

The balanced chemical equation follows:

3CaO+P_2O_5\rightarrow Ca_3(PO_4)_2

This is considered as synthesis reaction.

  • <u>Option 3:</u> Magnesium chloride reacting with silver nitrate to produce magnesium nitrate and silver chloride

The balanced chemical equation follows:

MgCl_2+2AgNO_3\rightarrow 2AgCl+Mg(NO_3)_2

This is considered as double displacement reaction.

  • <u>Option 4:</u> Sodium carbonate reacting with sulfuric acid to produce sodium sulfate, carbon dioxide and water

The balanced chemical equation follows:

Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+CO_2+H_2O

This is considered as double displacement reaction.

  • <u>Option 5:</u> Iron(II) sulfide reacting with hydrochloric acid to produce iron (II) chloride and hydrogen sulfide

The balanced chemical equation follows:

FeS+2HCl\rightarrow FeCl_2+H_2S

This is considered as double displacement reaction.

Hence, the reactions are written above.

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Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

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7 0
1 year ago
How many bonds are broken in 2O2
nirvana33 [79]

Answer:

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8 0
3 years ago
With reference to He-4 (or the diagram), explain the term isotopes.
boyakko [2]

Answer:

Isotopes are basically atoms of an element that have an unequal number of neutrons and protons. Of course the proton number remains the same, but the neutron number either decreases or increases, which leads to an overall change in mass. However, no chemical properties of the atom/element are changed as the electrons are the same number and do not react. In regards to Helium 4, the original number of neutrons in Helium is 2, and protons 2 as well. We see an equal number of neutrons and protons, hence an unchanged mass, and the element is <em>not</em> an isotope.

6 0
3 years ago
The following reactions can be used to prepare samples of metals. Determine the enthalpy change under standard state conditions
mamaluj [8]

Answer:

a) 62.1 kJ/mol

b) 2.82 kJ/mol

c) 270.91 kJ/mol

d) -851.5 kJ/mol

Explanation:

The enthalpy change for a reaction in standard conditions (ΔH°rxn) can be calculated by:

ΔH°rxn = ∑n*ΔH°f, products - ∑n*ΔH°f, reagents

Where n is the number of moles in the stoichiometry reaction, and ΔH°f is the enthalpy of formation at standard conditions. ΔH°f = 0 for substances formed by only a single element. The values can be found in thermodynamics tables.

a) 2Ag₂O(s) → 4Ag(s) + O₂(g)

ΔH°f, Ag₂O(s) = -31.05 kJ/mol

ΔH°rxn = 0 - (2*(-31.05)) = 62.1 kJ/mol

b) SnO(s) + CO(g) → Sn(s) + CO₂(g)

ΔH°f,SnO(s) = -285.8 kJ/mol

ΔH°f,CO(g) = -110.53 kJ/mol

ΔH°f,CO₂(g) = -393.51 kJ/mol

ΔH°rxn = [-393.51] - [-110.53 - 285.8] = 2.82 kJ/mol

c) Cr₂O₃(s) + 3H₂(g) → 2Cr(s) + 3H₂O(l)

ΔH°f,Cr₂O₃(s) = -1128.4 kJ/mol

ΔH°f,H₂O(l) = -285.83 kJ/mol

ΔH°rxn = [3*(-285.83)] - [( -1128.4)] = 270.91 kJ/mol

d) 2Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2Fe(s)

ΔH°f,Fe₂O₃(s) = -824.2 kJ/mol

ΔH°f,Al₂O₃(s) = -1675.7 kJ/mol

ΔH°rxn = [-1675.7] - [-824.2] = -851.5 kJ/mol

3 0
3 years ago
Na2CrO4 + PbCL2<br> Formula in double replacement
Marta_Voda [28]

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

<u>Explanation:</u>

In a double displacement reaction, the reactants which are involved in the reaction exchanging their ions thereby produces 2 new compounds. Here sodium chromate and lead chloride are undergoing double displacement reaction, the ions exchanges their position there by forming sodium chloride and lead chromate. So the double displacement reaction is given as,

Na₂CrO₄ + PbCl₂ → PbCrO₄ + 2 NaCl

6 0
3 years ago
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