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In-s [12.5K]
2 years ago
5

If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?

Physics
1 answer:
steposvetlana [31]2 years ago
3 0

Hi there!

\large\boxed{\text{B) 20 meters}}

We know that:

E_T = U + K

U = Potential Energy (J)

K = Kinetic Energy (J)

E = Total Energy (J)

At 10m, the total amount of energy is equivalent to:

U + K = 50 + 50 = 100 J

To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:

100J = mgh

We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².

50J = 10(10)m

m = 1/2 kg

Now, solve for height given that E = 100 J:

100J = 1/2(10)h

100J = 5h

<u>h = 20 meters</u>

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Answer:

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Explanation:

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Now, range of scale is from 0 to 200 N. So, maximum force, the spring can hold is 200 N. For this maximum force, the extension in the spring is equal to the length of the scale. So, x = 0.11\ m

Now, we know that, spring force is given as:

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Squaring both sides and expressing it in terms of 'm', we get:

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Now, plug in the given values and solve for 'm'. This gives,

m=\frac{1818.18\ N/m}{4\pi^2\times (2.55\ Hz)^2}\\\\m=\frac{1818.18\ N/m}{256.708\ Hz^2}\\\\m=7.08\ kg

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4 0
3 years ago
During a compression test, a cylinder has 40 percent of the specified compression reading. When the technician performs a wet te
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Answer:

Worn out piston rings

Explanation:

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Answer:

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Explanation:

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