If at 10m above the ground an object has 50J of Kinetic Energy, with 50J of Potential Energy. How high can the object travel?
1 answer:
Hi there!
We know that:
U = Potential Energy (J)
K = Kinetic Energy (J)
E = Total Energy (J)
At 10m, the total amount of energy is equivalent to:
U + K = 50 + 50 = 100 J
To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:
100J = mgh
We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².
50J = 10(10)m
m = 1/2 kg
Now, solve for height given that E = 100 J:
100J = 1/2(10)h
100J = 5h
<u>h = 20 meters</u>
You might be interested in
To solve this problem we will apply the normal distribution, with which we will obtain the probability that the given event will occur. Concepts such as the mean and standard deviation will be present throughout the solution of the problem. Increasing or decreasing the average would change the location or center point of the curve. The change in the standard deviation would lead to the change in the dispersion of the data. As the standard deviation increases, the curve would become flatter.
Let X be the output voltage of power supply
X∼N
A
The lower and upper specifications for voltage are 4.95 V and 5.05 V, respectively
Hence probability that a power supply selected at random will conform to the specifications on voltage is 0.9876
The resistance of the piece of wire is
where
is the resistivity of the copper
is the length of the piece of wire
is the cross sectional area of the wire
By substituting these values, we find the value of R:
Then, by using Ohm's law, we find the potential difference between the two points of the wire:
where
By substituting these values, we find the value of R:
Then, by using Ohm's law, we find the potential difference between the two points of the wire: