So we want to know what will happen if we put a magnetically soft material in a strong magnetic field. A magnetically soft material is a material whose magnetic field can easily be reversed. Those are ferromagnetic materials. Iron is such a material. When a magnetically soft material is placed into a strong magnetic field it gets its own magnetic field. But its not a permanent magnetic field, it can be changed by a different strong magnetic field.
Answer:
This question can be answered by using conversation of energy.
Explanation:
Note that we take 
because we are looking for the minimum initial speed for the penguin to reach the top of the second hill. Any other speed more than this will already be enough for him.
A sample of nitrogen gas has a volume of 5.0 ml at a pressure of 1.50 atm. what is the pressure exerted by the gas if the volume increases to 30.0 ml, at constant temperature is 0.25atm.
On constant temperature, the pressure and volume relation become constant before and after the change in quantitities have occurred.
According to Boyle's Law,
P₁V₁ = P₂V₂
where, P₁ is pressure exerted by the gas initially
V₁ is the volume of gas initially
P₂ is pressure exerted by the gas finally
V₂ is the volume of gas finally
Given,
P₁ = 1.5 atm
V₁ = 5 ml
V₂ = 30 ml
P₂ =?
On substituting the given values in the above equation:
P₁V₁ = P₂V₂
1.5 atm × 5 ml = P₂ × 30 ml
P₂ = 0.25 atm
Hence, pressure exerted by the gas is 0.25atm.
Learn more about Boyle's Law here, brainly.com/question/1437490
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Answer:
54 N
Explanation:
Draw a free body diagram. There are four forces acting on the balloon. Buoyant force pushing the balloon up, gravity pulling the helium down, gravity pulling the balloon skin down, and gravity pulling the load down.
Apply Newton's second law:
∑F = ma
B − Wh − Wb − L = ma
When the load is at a maximum, the acceleration is 0:
B − Wh − Wb − L = 0
B − Wh − Wb = L
B − mh g − Wb = L
The mass of the helium is its density times its volume:
B − ρh Vh g − Wb = L
Buoyant force is defined as B = ρVg, where ρ is the density of the displaced fluid (in this case, air), V is the volume of the displaced fluid, and g is acceleration of gravity. Since the volume of displaced air = the volume of the helium:
ρa V g − ρh V g − Wb = L
(ρa − ρh) V g − Wb = L
Given that ρa = 0.90 kg/m³, ρh = 0.178 kg/m³, V = 20 m³, g = 9.8 m/s², and Wb = 88 N:
(0.9 − 0.178) (20) (9.8) − (88) = L
L = 53.5 N
Rounded to 2 sig-figs, the maximum load that can be supported is 54 N.
