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spin [16.1K]
3 years ago
8

Multi-Select Question

Physics
1 answer:
dalvyx [7]3 years ago
7 0

Answer:

Correct Options :

<u>Acceleration on Earth: 1.6 m/s</u>

<u>Mass on the Moon: 100 </u><u>kg</u>

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20 characters or more
andreev551 [17]

Answer:

yes 20 characters or more

Explanation:

3 0
2 years ago
A 10kg oil is heated by a source of heat that supplies 800J of heat every minute. Calculate The heat added to oil after 30 minut
goblinko [34]

Answer:

4,200 joules per kilogram per degree Celsius

Explanation:

The specific heat capacity of a material is the energy required to raise one kilogram (kg) of the material by one degree Celsius (°C). The specific heat capacity of water is 4,200 joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C.

4 0
2 years ago
When an object is in a gravitational field, it has energy in its __________ __________ energy store.what’s is the word in the mi
lisabon 2012 [21]

Answer:

I don't know if this is right or not but I think its Potential Energy

Explanation:

8 0
3 years ago
(A) how much work is done when you push a crate horizontally with 100 N across a 10-m factory floor?
Mila [183]

Answer:

A) 1000 joules

Explanation:

In general work is given by the equation:

W=\intop_{a}^{b}\overrightarrow{F}\cdot d\overrightarrow{s} (1)

A) With \overrightarrow{s} the displacement and \overrightarrow{F} the force applied, because the force and the displacement are parallel (the crate is pushed horizontally) \overrightarrow{F}\cdot d\overrightarrow{s} is simply F\,ds, and because the path is a straight line and the force is constant work is:

W=FS (2),

W=(100)(10)=1000\,J

B) The work-energy theorem says that the total work on a body is equal to the change on kinetic energy:

W_{tot}=\varDelta K (3)

The total work on the crate is the work done by the push and plus the work of the friction W_{tot}=W + W_{f} (4) , as (A) because forces are parallel to the displacement W= FS (5) and W_{f}=-fS (6), the due friction always has negative sign because is opposite to the displacement, using (6), (5) and (4) on (3):

FS-fS=\varDelta K (3)

1000-(70)(10)=300\,J

C) The energy is lost by friction, so the amount of energy turned into heat is the work the friction does:

Q=fS=(70)(100)=700\,J (3)

6 0
3 years ago
A playground merry-go-round has radius 2.10m and moment of inertia 2500kg*m^2 about a vertical axle through its center, and it t
vladimir2022 [97]

Answer

Radius of the wheel r = 2.1 m

Moment of inertia I = 2500 Kg m²

Tangential force applied F = 18 N

Time interval t = 16 s

Initial angular speed ω1 = 0

Final angular speed ω2 = ?

Let α be the angular acceleration.

Torque applied τ = Iα

                         F r = Iα

Angular acceleration α = F r/I

                                    = \dfrac{18\times 2.1}{2500}

                                    = 0.015 rad/s²

(a)From rotational kinematic relation

            Final angular speed ω₂ = ω₁ + αt

                                                 = 0 + (0.015 rad/s^2 * 16 s)

                                                 = 0.24 rad/s

(b) Work done W = 0.5 Iω₂² - (1/2)Iω₁²

                      = 0.5*( 2500 Kg m²)(0.24 rad/s)^2 - 0

                      =  72 J

(c) Average power supplied by the child P = W/t = \dfrac{72}{16}

                                                                        = 4.5 watt        

8 0
3 years ago
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