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maxonik [38]
3 years ago
5

A block of mass 27.00 kg sits on a horizontal surface with, coefficient of kinetic

Physics
1 answer:
zhannawk [14.2K]3 years ago
5 0

Answer:

The force is  F  = 172 \ N

Explanation:

From the question we are told that

    The  mass of the block is  m_b  = 27.0 \ kg

     The  coefficient of  static friction is  \mu_s  =  0.65

     The coefficient of kinetic friction is  \mu_k  =  0.50

The  normal force acting on the block is  

      N  =  m *  g

substituting values

     N  =   27 *  9.8

     N  =   294.6  \  N

Given that the force we are to find is the force required to get the block to start moving then the force acting against this force is the static frictional force which is mathematically evaluated as

        F_f  =  \mu_s  *  N

substituting values

        F_f  =   0.65 *  264.6

        F_f  =   172 \ N

Now for this  block to move the force require is  equal to F_f i.e

       F= F_f

=>    F  = 172 \ N

       

   

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A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
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<h3>What's the velocity of the ball at the highest point of the trajectory?</h3>
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  • However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ.
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<h3>What's the acceleration of the ball at the highest point of projectile?</h3>
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Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory

A- neither the ball's velocity nor its acceleration are zero.

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brainly.com/question/24216590

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