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rodikova [14]
2 years ago
11

if a person can jump maximum along distance of 3m ,on the earth how far could be jump on the moon where acceleration due to grav

ity is 1÷16 of that on the earth​
Physics
1 answer:
allochka39001 [22]2 years ago
8 0

Answer:

The person can jump 48 m on the Moon

Explanation:

The question parameters are;

The maximum long jump distance of a person on Earth, R_{max} = 3 m

The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth

The distance the person can jump on the Moon is given as follows;

A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile

The horizontal range, R_{max}, of a projectile motion is found by using the following formula

R_{max} = \dfrac{u^2}{g}

Where;

g = The acceleration due to gravity = 9.8 m/s²

Therefore, we have;

R_{max} = 3 \, m = \dfrac{u^2}{9.8 \, m/s^2 }

u² = 3 m × 9.8 m/s² = 29.4 m²/s²

Therefore, on the Moon, we have;

The acceleration due to gravity on the Moon, g_{Moon} = 1/16 × g

∴ g_{Moon} = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²

R_{max \ Moon} = \dfrac{u^2}{g_{Moon}}   = \dfrac{29.4 \ m^2/s^2}{0.6125 \, m/s^2 } \approx 48 \, m

The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is R_{max \ Moon} ≈ 48 m

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A bat at rest sends out ultrasonic sound waves at 46.2 kHz and receives them returned from an object moving directly away from i
murzikaleks [220]

Answer:

f" = 40779.61 Hz

Explanation:

From the question, we see that the bat is the source of the sound wave and is initially at rest and the object is in motion as the observer, thus;

from the Doppler effect equation, we can calculate the initial observed frequency as:

f' = f(1 - (v_o/v))

We are given;

f = 46.2 kHz = 46200 Hz

v_o = 21.8 m/s

v is speed of sound = 343 m/s

Thus;

f' = 46200(1 - (21/343))

f' = 43371.4285 Hz

In the second stage, we see that the bat is now a stationary observer while the object is now the moving source;

Thus, from doppler effect again but this time with the source going away from the obsever, the new observed frequency is;

f" = f'/(1 + (v_o/v))

f" = 43371.4285/(1 + (21.8/343))

f" = 40779.61 Hz

4 0
2 years ago
How many newtons of force are required to move a 54.87 kg object with an acceleration of 9.8 m/s/s?
vodka [1.7K]
Force equals mass*acceleration
F = ma

Given m = 54.87 kg, a = 9.8 m/s^2

F = (54.87)(9.8)
F = 537.726
F = 538 N

A force of al least 538 Newtons is required to move the object.
7 0
2 years ago
Need help with two physics questions!
nikitadnepr [17]

1) The north component of the airplane velocity is 260 km/h.

2) The direction of the plane is 24^{\circ} north of east.

Explanation:

1)

In this problem, we have to resolve the velocity vector into its components.

Taking east as positive x-direction and north as positive y-direction, the components of the velocity along the two directions are given by:

v_x = v cos \theta

v_y = v sin \theta

where

v is the magnitude of the velocity

\theta is the angle between the direction of the velocity and the positive x-axis (the east direction)

For the airplane in this problem,

v = 750 km/h

\theta=20^{\circ}

So, the two components are

v_x = (750)(cos 20)=704.8 km/h

v_y = (750)(sin 20)=256.5 km/h

So, the component in the north direction is 256.5 km/h, so approximately 260 km/h.

2)

In this problem, we have to use vector addition.

In fact, the motion of the plane consists of two displacements:

- A first displacement of 220 km in the east direction

- A second displacement of 100 km in the north direction

Using the same convention of the same problem (x = east and y = north), we can write

d_x = 220 km

d_y = 100 km

Since the two vectors are perpendicular to each other, we can find their magnitude using Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{(220)^2+(100)^2}=241.7 km

And the direction is given by

\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{100}{220})=24^{\circ} north of east.

Learn more about vectors here:

brainly.com/question/2678571

brainly.com/question/4945130

brainly.com/question/2678571

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#LearnwithBrainly

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It’s c hope this helps :)
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Marina86 [1]

Answer:

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