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kenny6666 [7]
3 years ago
5

Exactly one mole of an ideal gas is contained in a 2.00-liter container at 1,000 K. What is the pressure exerted by this gas?

Chemistry
2 answers:
levacccp [35]3 years ago
7 0
Use PV =nRT

so P = nRT/V

= 1 mole(0.08205 L atm/K mol)(1000K) / 2 L

= 41 atm
ziro4ka [17]3 years ago
6 0

Answer : The pressure of the gas is, 41.025 atm

Solution :

Using ideal gas equation :

PV=nRT\\\\P=\frac{nRT}{V}

where,

n = number of moles of gas  = 1 mole

P = pressure of the gas = ?

T = temperature of the gas = 1000 K

R = gas constant = 0.08205 L.atm/mole.K

V = volume of gas = 2.00 L

Now put all the given values in the above equation, we get the pressure of the gas.

P=\frac{nRT}{V}

P=\frac{1mole\times (0.08205L.atm/mole.K)\times 1000K}{2.00L}

P=41.025atm

Therefore, the pressure of the gas is, 41.025 atm

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Answer: The empirical formula is CH_2 and molecular formula is C_4H_8

Explanation:

We are given:

Mass of CO_2 = 18.95 g

Mass of H_2O= 7.759 g

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Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 18.59 g of carbon dioxide, =\frac{12}{44}\times 18.59=5.07g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 7.759 g of water, =\frac{2}{18}\times 7.759=0.862g of hydrogen will be contained.

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Step 1 : convert given masses into moles.

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Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.862g}{1g/mole}=0.862moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.422}{0.422}=1

For H =\frac{0.862}{0.422}=2

The ratio of C : H = 1: 2

Hence the empirical formula is CH_2.

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Now we have to calculate the molecular formula.

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The molecular formula will be=4\times CH_2=C_4H_8

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