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kenny6666 [7]
3 years ago
5

Exactly one mole of an ideal gas is contained in a 2.00-liter container at 1,000 K. What is the pressure exerted by this gas?

Chemistry
2 answers:
levacccp [35]3 years ago
7 0
Use PV =nRT

so P = nRT/V

= 1 mole(0.08205 L atm/K mol)(1000K) / 2 L

= 41 atm
ziro4ka [17]3 years ago
6 0

Answer : The pressure of the gas is, 41.025 atm

Solution :

Using ideal gas equation :

PV=nRT\\\\P=\frac{nRT}{V}

where,

n = number of moles of gas  = 1 mole

P = pressure of the gas = ?

T = temperature of the gas = 1000 K

R = gas constant = 0.08205 L.atm/mole.K

V = volume of gas = 2.00 L

Now put all the given values in the above equation, we get the pressure of the gas.

P=\frac{nRT}{V}

P=\frac{1mole\times (0.08205L.atm/mole.K)\times 1000K}{2.00L}

P=41.025atm

Therefore, the pressure of the gas is, 41.025 atm

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Iron and carbon monoxide are made by heating 5.53 kg of iron ore, Fe₂O₃, and carbon. What is the theoretical yield of iron in ki
vfiekz [6]

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Mass of Fe produced = 3.86785211069  ≈ 3.87 kg

Explanation:

From the question the chemical reaction can be written as follow :

Fe2O3 + C → Fe + CO  

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Fe2O3 + 3C → 2Fe + 3CO  

compute the molecular mass of Fe2O3 and atomic mass of Iron(Fe)

Molecular mass of Fe2O3 = 55.845(2) + 15.999(3) = 111.69 + 47.997 = 159.687 g

Atomic mass of iron = 55.845 g

From the balanced equation

159.687 g of Fe2O3  produces 2 ×  55.845 = 111.69 g of Fe(iron)

Convert the 5.53 kg to gram

1 kg = 1000 g

5.53 kg  = 5.53 × 1000 = 5530 g

since,

159.687 g of Fe2O3  produces 2 ×  55.845 = 111.69 g of Iron(Fe)

5530 g of  Fe2O3  will produce  

cross multiply

Mass of Fe produced =5530 × 111.69/159.687

Mass of Fe produced = 617645.7

/159.687

Mass of Fe produced = 3867.85211069  g

convert to kg

1000 g = 1 kg

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Mass of Fe produced = 3.86785211069  ≈ 3.87 kg

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3 years ago
If the lab technician needs 30 liters of a 25% acid solution, how many liters of the 10% and the 30% acid solutions should she m
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Answer:

7.5 L of the 10% and 22.5 L of the 30% acid solution, she should mix.

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Let the volume of 10% acid solution used to make the mixture = x L

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<u>x = 7.5 L </u>

<u>y = 22.5 L</u>

6 0
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