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Dvinal [7]
3 years ago
15

During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t2 to so

lve your answer. (Do not forget to keep units in your answer.)
Physics
2 answers:
Temka [501]3 years ago
8 0

I believe that formula is incomplete, if it is derived from the kinematic equations.

The full formula being s=ut+\frac{1}{2}at^{2}

where:

s is the displacement (or how far she travelled in your question)

u is the initial velocity, which I think can be assumed to be 0 m/s

t is the time taken which is 120 s

a is the acceleration due to gravity which points down in a negative y direction, which is -9.8 m/s^{2}

Since initial velocity, u, is assumed to be 0 m/s the equation becomes:

s=\frac{1}{2}at^{2}

Substitute in a = -9.8m/s^{2}  and t = 120 s and calculate your answer.

Tell me what you calculate the answer to be (don't forget units) and I'll let you know if it's right.

m_a_m_a [10]3 years ago
8 0

The answer would be

70560m

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Answer:

Definimos momento como el producto entre la masa y la velocidad

P = m*v

(tener en cuenta que la velocidad es un vector, por lo que el momento también será un vector)

Sabemos que el peso de la paca de heno es 175N, y el peso es masa por aceleración gravitatoria, entonces.

Peso = m*9.8m/s^2 = 175N

m = (175N)/(9.8m/s^2) = 17.9 kg

Ahora debemos calcular la velocidad de la paca justo antes de tocar el suelo.

Sabemos que la velocidad horizontal será la misma que tenía el avión, que es:

Vx = 36m/s

Mientras que para la velocidad vertical, usamos la conservación de la energía:

E = U + K

Apenas se suelta la caja, esta tiene velocidad cero, entonces su energía cinética será cero y la caja solo tendrá energía potencial (Si bien la caja tiene velocidad horizontal en este punto, por la superposición lineal podemos separar el problema en un caso horizontal y en un caso vertical, y en el caso vertical no hay velocidad inicial)

Entonces al principio solo hay energía potencial:

U = m*g*h

donde:

m = masa

g = aceleración gravitatoria

h = altura  

Sabemos que la altura inicial es 60m, entonces la energía potencial es:

U = 175N*60m = 10,500 N

Cuando la paca esta próxima a golpear el suelo, la altura h tiende a cero, por lo que la energía potencial se hace cero, y en este punto solo tendremos energía cinética, entonces:

10,500N = (m/2)*v^2

De acá podemos despejar la velocidad vertical justo antes de golpear el suelo.

√(10,500N*(2/ 17.9 kg)) = 34.25 m/s

La velocidad vertical es 34.25 m/s

Entonces el vector velocidad se podrá escribir como:

V = (36 m/s, -34.25 m/s)

Donde el signo menos en la velocidad vertical es porque la velocidad vertical es hacia abajo.

Reemplazando esto en la ecuación del momento obtenemos:

P = 17.9kg*(36 m/s, -34.25 m/s)  

P = (644.4 N, -613.075 N)

6 0
3 years ago
A car slows down from 27.7 m/s <br> to 10.9 m/s in 2.37 s. <br> What is its acceleration?
Sunny_sXe [5.5K]

Answer:

- 7.088 m/s²

Explanation:

As we know that,

★ Acceleration = Change in velocity/Time

→ a = (v - u)/t

Here,

  • Initial velocity (u) = 27.7 m/s
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→ a = (10.9 m/s - 27.7 m/s)/2.37 s

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alex41 [277]

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Explanation:

Step 1:

Speed of sound in water varies from 1450 to 1498 meters per second

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Speed of sound in warm air is approximately 338.89 meters per second

Speed of sound in cold air is approximately 293.33 meters per second

Step 2:

In warm air sound travels faster than that of sound travelling nature in cold air.

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Answer:

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