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vivado [14]
3 years ago
9

Which best describes electrical energy? a. energy released by a chemical reaction b. energy produced by flow of electric charge

c. energy released by nuclear reaction
Physics
2 answers:
inessss [21]3 years ago
4 0
<span> energy produced by flow of electric charge describes a electrical energy
because movement of electric charge do effect the work on system 
so correct option is B 
hope it helps</span>
Zarrin [17]3 years ago
4 0

Answer:

b. energy produced by flow of electric charge

Explanation:

Electric energy is produced due to the existence of an electric current, that is, the flow of electric charge (electrons). Each time a switch is activated, the flow of electrons is generated through the metallic conductor cable, since metals have a greater amount of free electrons than other materials.

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A uniformly charged ring of radius 10.0 cm has a total charge of 75.0 mC. Find the electric field on the axis of the ring at (a)
wlad13 [49]

Answer:

(a) 6650246.305 N/C

(b) 24150268.34 N/C

(c) 6408227.848 N/C

(d) 665024.6305 N/C

Explanation:

Given:

Radius of the ring (r) = 10.0 cm = 0.10 m           [1 cm = 0.01 m]

Total charge of the ring (Q) = 75.0 μC = 75\times 10^{-6}\ \mu C    [1 μC = 10⁻⁶ C]

Electric field on the axis of the ring of radius 'r' at a distance of 'x' from the center of the ring is given as:

E_x=\dfrac{kQx}{(x^2+r^2)^\frac{3}{2}}

Plug in the given values for each point and solve.

(a)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=1.00\ cm=0.01\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.01)}{((0.01)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{6750}{1.015\times 10^{-3}}\\\\E_x=6650246. 305\ N/C

(b)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=5.00\ cm=0.05\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.05)}{((0.05)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{33750}{1.3975\times 10^{-3}}\\\\E_x=24150268.34\ N/C

(c)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=30.0\ cm=0.30\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(0.30)}{((0.30)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{202500}{0.0316}\\\\E_x=6408227.848\ N/C

(d)

Given:

Q=75\times 10^{-6}\ \mu C, r=0.01\ m, a=100\ cm=1\ m,k=9\times 10^{9}\ Nm^2/C^2

Electric field is given as:

E_x=\dfrac{(9\times 10^{9})(75\times 10^{-6})(1)}{((1)^2+(0.1)^2)^\frac{3}{2}}\\\\E_x=\dfrac{675000}{1.015}\\\\E_x=665024.6305\ N/C

7 0
3 years ago
What is trapezord mean
igor_vitrenko [27]
A quadrilateral with only one pair of parallel sides.
<span>a small carpal bone in the base of the hand, articulating with the metacarpal of the index finger.
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5 0
3 years ago
A ground-fault circuit interrupter shuts down a circuit if it?
alukav5142 [94]
C: if it senses unequal currents
6 0
1 year ago
Massive stars terminate in a brilliant explosion called a
BigorU [14]

super nova is named for such explosion

6 0
3 years ago
An object of mass 3 kg, moving with and sticks to an object of mass 2.00 kg with an initial velocity of 3.00 m/s. Find the final
Aleonysh [2.5K]

Answer:

1.8 m/s

Explanation:

momentum = mass × velocity

initial momentum = m1v1+m2v2

                             = 3×3 +2×0 = 9+0= 9 kg m/s

let combined velocity be V

HENCE  

final momentum = total mass × velocity

                            = (3+2) × V = 5V

According to law of conservation of momentum

final momentum = initial momentum

5V = 9

V =9/5

V = 1.8 m/s

8 0
3 years ago
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