3 years ago

2. Derive an expression for the final velocity of an object dropped from some height (h)

Physics

1 answer:

elixir [45]3 years ago

7 0

Answer:

v = √(2gh)

Explanation:

Given:

Δy = h

v₀ = 0

a = g

Find: v

v² = v₀² + 2aΔy

v² = (0)² + 2gh

v = √(2gh)

You can also prove this with conservation of energy.

PE = KE

mgh = ½mv²

v = √(2gh)

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