Here we can use coulomb's law to find the force between two charges
As per coulombs law
]tex]F = \frac{kq_1q_2}{r^2}[/tex]
here we have
now by using the above equation we have
so here the force between two charges is of above magnitude and this will be repulsive force between them as both charges are of same sign.
I think is between A&B
I think I would answer B
The cup is acted upon by an unbalanced force which is the cars acceleration, but before it was an object at rest that stayed at rest. This jet propels their body forward.
Yes, yes, we know all of that. It certainly took you long enough to
get around to asking your question.
If
a = (14, 10.5, 0)
and
b = (4.62, 9.45, 0) ,
then, to begin with, neither vector has a z-component, and they
both lie in the x-y plane.
Their dot-product a · b = (14 x 4.62) + (10.5 x 9.45) =
(64.68) + (99.225) = 163.905 (scalar)
I feel I earned your generous 5 points just reading your treatise and
finding your question (in the last line). I shall cherish every one of them.
