<span>Pressure = force / area</span>
I assume that 350kg is the mass
Therefore,
350 x 9.8 (gravity) = 3430N
3430 / 1 = 3430Pa
3.43 KPa
Answer: The reason a light bulb glows is that electricity is forced through tungsten, which is a resistor. The energy is released as light and heat. A conductor is the opposite of a resistor. Electricity travels easily and efficiently through a conductor, with almost no other energy released as it passes.
Explanation:
Answer:
The wavelength of the radiation absorbed by ozone is 319.83 nm
Explanation:
Given;
frequency of absorbed ultraviolet (UV) radiation, f = 9.38×10¹⁴ Hz
speed of the absorbed ultraviolet (UV) radiation, equals speed of light, v = 3 x 10⁸ m/s
wavelength of the absorbed ultraviolet (UV) radiation, λ = ?
Apply wave equation for speed, frequency and wavelength;
v = fλ
λ = v / f
λ = (3 x 10⁸) / (9.38×10¹⁴)
λ = 3.1983 x 10⁻⁷ m
λ = 319.83 x 10⁻⁹ m
λ = 319.83 nm
Therefore, the wavelength of the radiation absorbed by ozone is 319.83 nm
Answer:
<u>We are given: </u>
initial velocity (u) = 0 m/s
final velocity (v) = 10 m/s
displacement (s) = 20 m
acceleration (a) = a m/s/s
<u>Solving for 'a'</u>
From the third equation of motion:
v² - u² = 2as
replacing the variables
(10)² - (0)² = 2(a)(20)
100 = 40a
a = 100 / 40
a = 2.5 m/s²
Answer:
a) - 72.5°c
b) pressure = 3625.13 Pa
c) density = 0.063 kg/m^3
d) it is a subsonic aircraft
Explanation:
a) Determine Temperature
Temperature at 19.5 km ( 19500 m )
T = -131 + ( 0.003 * altitude in meters )
= -131 + ( 0.003 * 19500 ) = - 72.5°c
b) Determine pressure and density at 19.5 km altitude
Given :
Po (atmospheric pressure at sea level ) = 101kpa
R ( gas constant of air ) = 0.287 KJ/Kgk
T = -72.5°c ≈ 200.5 k
pressure = 3625.13 Pa
hence density = 0.063 kg/m^3
attached below is the remaining part of the solution
C) determine if the aircraft is subsonic or super sonic
Velocity ( v ) = 
= 
= 283.8 m/s
hence it is a subsonic aircraft
