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denpristay [2]
2 years ago
11

2. Derive an expression for the final velocity of an object dropped from some height (h)

Physics
1 answer:
elixir [45]2 years ago
7 0

Answer:

v = √(2gh)

Explanation:

Given:

Δy = h

v₀ = 0

a = g

Find: v

v² = v₀² + 2aΔy

v² = (0)² + 2gh

v = √(2gh)

You can also prove this with conservation of energy.

PE = KE

mgh = ½mv²

v = √(2gh)

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Answer:

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1. Why does Earth's moon have no atmosphere
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Two long, straight wires are parallel and 26 cm apart.
mezya [45]

Answer: 2.49×10^-3 N/m

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By substituting the parameters, we have that

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= 4080.744×10^-6/ 1.634

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5 0
3 years ago
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