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denpristay [2]
3 years ago
11

2. Derive an expression for the final velocity of an object dropped from some height (h)

Physics
1 answer:
elixir [45]3 years ago
7 0

Answer:

v = √(2gh)

Explanation:

Given:

Δy = h

v₀ = 0

a = g

Find: v

v² = v₀² + 2aΔy

v² = (0)² + 2gh

v = √(2gh)

You can also prove this with conservation of energy.

PE = KE

mgh = ½mv²

v = √(2gh)

You might be interested in
A horizontal spring required a force of 1.0 N to compress it 0.1 m. How much work is required to stretch the spring 0.4 m?
Crank

Answer:

<h2>0.5J</h2>

Explanation:

given data

Force applied F= 1N

extension e= 0.1m

let us find the spring constant first

applying

F=ke

k=F/e

k=1/0.1

k=10N/m

Step two:

Required is the work done

we know that the expression/formula for the work done by a spring is given as

Wd=1/2kx^2

x=0.4m

substitute

Wd= 1/2*10*0.4^2

Wd=0.5*10*0.16

Wd=0.5J

3 0
3 years ago
Refrigerators are usually kept at about 5∘C, while room temperature is about 20∘C. If you were to take an "empty" sealed 2-liter
expeople1 [14]

Answer:

The volume will not contract to one fourth of the original.

Explanation:

Applying Charles's Law as:

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = ?

V₂ = 2 L

T₁ = 5 °C

T₂ = 20 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,

T₁ = (5 + 273.15) K = 278.15 K  

T₂ = (20 + 273.15) K = 293.15 K  

Using Charles law as:

V_1=\frac {V_2}{T_2} \times {T_1}

V_1=\frac {2\ L}{293.15 K} \times {278.15 K}

V_1=1.8977 L

Thus, the volume will not contract to one fourth of the original. (1/4 of 2 L is 0.5 L).

8 0
4 years ago
Before partacting, if correct marked as brainest
Molodets [167]

Answer:

C. Basic swimming capability.

Explanation:

one of the way before participating in any water-based sport is know how to do the basic swimming way.

7 0
3 years ago
The sampling rate of an ADC is 8.1 kHz. What will be an appropriate cut-off frequency (break frequency) for the anti-aliasing fi
KiRa [710]

Answer:

4000 Hz

Explanation:

An anti-alias filter is usually added in front of the ADC to limit a certain range of input frequencies in order to avoid aliasing. This filter is usually a low pass filter that passes low frequencies but attenuates the high frequencies.

The Nyquist sampling criteria states that the sampling rate should be at least twice the maximum frequency component of the desired signal.

Sampling rate = 2(max input frequency)

From the relation we can find out the cut-off frequency for the anti-aliasing filter.

max input frequency = sampling rate/2

max input frequency = 8100/2 = 4050 Hz

Therefore, 4000 Hz would be an appropriate cut-off frequency for the anti-aliasing filter.

3 0
3 years ago
A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average forc
elena-14-01-66 [18.8K]

Answer:4.259 kN

Explanation:

Given

mass of bullet m=0.02 kg

final velocity of bullet v=575 m/s

time taken =2.7 ms\approx 2.7\times 10^{-3} s

We know

Impulse=F_{avg}\cdot t=change\ in\ momentum

thus

Initial Momentum(P_i)=m\times 0

Final Momentum(P_f)=m\times v=0.02\times 575

P_f=11.5 kg-m/s

F_{avg}\times 2.7\times 10^{-3}=P_f-P_i=11.5

F_{avg}=4.259\times 10^3

F_{avg}=4.259 kN

7 0
3 years ago
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