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krek1111 [17]
3 years ago
13

Find the sum and simplify if possible, estimate for reasonableness. 4 3/4+2 2/5?

Mathematics
2 answers:
Margarita [4]3 years ago
6 0
I think it is 7 and 3/20
aleksandr82 [10.1K]3 years ago
5 0
It is 7 1/3 hope it helped
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What is the probability a sample of 90 test takers will provide a sample mean test score within 10 points of the population mean
Elena-2011 [213]

Answer:

0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

Step-by-step explanation:

The following information is missing:

The standard deviation of population is 100.

We are given the following information in the question:

Population mean, μ = 502

Standard Deviation, σ = 100

Sample size, n  = 90

Standard error =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{100}{\sqrt{90}} =  10.54

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(test score within 10 points)

P(492 \leq x \leq 512) \\\\= P(\displaystyle\frac{492 - 502}{10.54} \leq z \leq \displaystyle\frac{512-502}{10.54}) \\\\= P(-0.9487 \leq z \leq 0.9487)\\= P(z \leq 0.9487) - P(z < -0.9487)\\= 0.829 -0.171 = 0.658 = 65.8\%

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0.658 is the probability that a sample 90 test takers will provide a sample mean test score within 10 points of the population mean of 502.

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3 years ago
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