Ab = (7x-6) → b = (7x-6)/a (1)
bc = (12-2x) → b = (12-2x)/c (2)
Since (1) = (2) → (7x-6)/a = (12-2x)/c OR a/c = (7x-6)/(12-2x) (3)
Multiply both numerators of (3) by the SQUARE of their respective denominators;
(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:
ac = (7x-6)(12x-2x) or ac = -14x² + 96x - 72
Answer:
Yes
Step-by-step explanation:
Given that a teacher prepares 26 tiles with 5 vowels numbered 1 and 21 consonants numbered 2.
The probability for drawing vowel =
Prob for consonant =
If number of trials is atleast 30 we can expect reliable results.
Here the results are recorded for 120 times at random.
Since number of trials is large, we can expect a reliable and accurate results representing the actual probability.
This is because more the number of trials, the less would be the margin of error i.edeviationfrom the expected probability would be minimum
Answer:
The first one
Step-by-step explanation:
To solve this problem,
we must first imagine out that the sequence of the children is either <span>
GBGBGB.... or BGBGBG....</span>
So there are 2
possible sequence all in all. Now to solve for the total arrangements per
sequence,<span> the
girls can be arranged in n! ways in their alloted spots, and so can the boys n!
in their alternate spots, therefore:
Total arrangements = 2 * n! * n!</span>
If n = 55
Total arrangements = 2
* 55! * 55!
Total arrangements = (The
answer is very big ~almost infinite)
If n = 5
Total arrangements = 2
* 5! * 5!
Total arrangements = 28,800
<span>So I believe the
correct given is 5 boys and 5 girls and there are a total of 28,800
arrangements.</span>
Answer:
Step-by-step explanation:
V = 1/3 pi r^2 h
r = d/2
r = 6/2 = 3
h = 4.5
V = 1/3 *3.14 * 3^2 * 4.5
V = 1/3 * 3.14 * 9 * 4.5
V = 1/3 * 127.17
V = 42.39
