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lesya [120]
3 years ago
11

Is the dehydration process a physical or chemical change? Why?

Chemistry
2 answers:
DanielleElmas [232]3 years ago
8 0
Dehydration is a chemical change because it deals with the chemical reaction of the loss of water, and any chemical change involves the formation or breaking of bonds. 

Answer: Chemical change
kotegsom [21]3 years ago
8 0
Physical because you can be dehydrated and BECOME hydrated which is a physical change because u can change it and a chemical change you cant change it
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Alina [70]

To determine the electronegativity for each bond you need to calculate the difference of electronegativity of the atoms forming the bond.  

If the difference is equal or greater than 1.7 you have an ionic bond.

If the difference is between 0.4 and 1.6  you have a polar covalent bond.

If the difference is between 0 and less than 0.4 you have a nonpolar covalent bond.  

1) In NH₃ there is a nitrogen - hydrogen bond.  

electronegativity of nitrogen - electronegativity of hydrogen =

3 - 2.2 = 0.8 → polar covalent bond

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electronegativity of nitrogen - electronegativity of nitrogen =

3 - 3 = 0 → nonpolar covalent bond

3) In H₂O there is an oxygen - hydrogen bond.  

electronegativity of oxygen - electronegativity of hydrogen =

3.5 - 2.2 = 1.3 → polar covalent bond

4) In PCl₃ there is a chlorine - phosphorus bond.  

electronegativity of chlorine - electronegativity of phosphorus = 3 - 2.1 = 0.9 → polar covalent bond

4) In HBr there is a bromine - hydrogen bond.  

electronegativity of bromine - electronegativity of hydrogen = 2.8 - 2.2 = 0.6 → polar covalent bond

5) In MgCl₂ there is a chlorine - magnesium bond.  

electronegativity of chlorine - electronegativity of magnesium = 3 - 1.2 = 1.8 → ionic bond

6) In F₂ there is a fluorine - fluorine  bond.  

electronegativity of fluorine - electronegativity of fluorine =

4 - 4 = 0 → nonpolar covalent bond

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electronegativity of oxygen- electronegativity of carbon =

3.5 - 2.5 = 1 → polar covalent bond

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electronegativity of chlorine - electronegativity of lithium =

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3 - 2.5 = 0.5 → polar covalent bond

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Answer:

See explanation

Explanation:

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As for 2-iodo-2-methylpropane, there is a polar C-I bond. This now implies that the intermolecular forces present are both dispersion forces and dipole interaction. As a result of the presence of stronger dipole interaction between 2-iodo-2-methylpropane molecules, the compound has a higher boiling point than  2-methylpropane.

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