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djyliett [7]
3 years ago
9

How does the geosphere and biosphere interact

Chemistry
1 answer:
Vlada [557]3 years ago
6 0

The geosphere, in turn, reflects the sun's energy back into the atmosphere. The biosphere receives gases, heat, and sunlight (energy) from the atmosphere.

Explanation:

  • The geosphere, in return reflects the sun's energy back into the atmosphere. The biosphere receives gases, heat, and sunlight energy from the atmosphere.
  • Scientists divide the planet into two the main components: the biosphere, which consists of all life.
  • The hydrosphere interacts with the geosphere when particles of water or rain cause land formations to erode.
  • biosphere is the part of the earth and its atmosphere capable of supporting life.
  • Geo sphere is the solid body of the earth.
  • Biosphere is the totality of living organisms and their environment.

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198 g of Glucose Is the answer.

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Mercury has an atomic number of 80 and a mass number of 200.
denis23 [38]
C. The mass number is the amount of Protons and electrons there are combined, so 200 - 80 is 120.
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Explanation:

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Calculate the mass of butane needed to produce 97.4 g of carbon dioxide. Express your answer to three significant figures and in
Vsevolod [243]

Answer:

32.1 g

Explanation:

Step 1: Write the balanced combustion reaction

C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O

Step 2: Calculate the moles corresponding to 97.4 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

97.4 g × 1 mol/44.01 g = 2.21 mol

Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide

The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol

Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀

The molar mass of C₄H₁₀ is 58.12 g/mol.

0.553 mol × 58.12 g/mol = 32.1 g

4 0
3 years ago
If the take off velocity of an airplane on a runway is 300 km /hr with an acceleration of 1 m/s2. What is the take off time of t
Rama09 [41]
<h3>Answer:</h3>

83.33 seconds.

<h3>Explanation:</h3>

<u>We are given;</u>

  • Take off velocity as 300 km/hr
  • Acceleration as 1 m/s²

We are required to calculate the take off time of the airplane.

<h3>Step 1: Convert velocity from km/hr to m/s </h3>

We are going to use the conversion factor.

The conversion factor is 3.6 km/hr per m/s

Therefore;

Velocity = 300 km/hr ÷ 3.6 km/hr per m/s

             = 83.33 m/s

<h3>Step 2: Calculate the take off time</h3>

We know that;

v = u + at

where, u is the initial velocity, v the final velocity, a the acceleration and t is time.

But, initial velocity is Zero

Therefore;

83.33 m/s = 1 m/s² × t

Thus;

time = 83.33 m/s ÷ 1 m/s²

       = 83.33 seconds

Therefore, the take off time is 83.33 seconds.

5 0
3 years ago
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