Calculate the molar concentration of HA (90.2 g/mol) in a solution that has a specific gravity of 1.24 and is 64% HNO3 (w/w).
1 answer:
Answer:
Explanation:
Hello,
In this case, considering the given specific gravity we are to compute the density of the 64% HNO3 solution:
In such a way, since the given solution of nitric acid is 64 % by mass, we've got:
Thus, by using the previously computed density and the molar mass of HA (90.2 g/mol) we can compute the required molar concentration as follows:
Regards.
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Answer : The number of moles of oxygen needed are, 1.5 moles.
Explanation :
The balanced chemical reaction will be:
Now we have to calculate the moles of oxygen.
From the balanced chemical reaction we conclude that,
As, 6 moles of water vapor produces from 5 moles of oxygen
So, 1.80 moles of water vapor produces from moles of oxygen
Therefore, the number of moles of oxygen needed are, 1.5 moles.
La aspirina se prepara haciendo reaccionar ácido salicílico con exceso de anhídrido etanoico. En un experimento, 50.05 g de ácido salicílico se convirtieron en 55.45 g de aspirina. ¿Cuál fue el porcentaje de rendimiento?
<em>In English:</em>
Aspirin is prepared by reacting salicylic acid with excess ethanoic anhydride. In one experiment, 50.05 g of salicylic acid was converted to 55.45 g of aspirin. What was the yield percentage?
Answer:
el rendimiento porcentual para la cantidad dada de ácido salicílico es 84.99 %
<em>In English:</em>
<em>the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>
<em></em>
Explanation:
La ecuación química equilibrada para la reacción se puede escribir como:
C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + HC₂H₃O₂
Para la reacción mostrada arriba; El reactivo limitante de la reacción es el ácido salicílico. Ahora; calcular el porcentaje de rendimiento; se espera que primero determinemos el rendimiento teórico de la reacción.
Entonces; la fórmula para calcular el porcentaje de rendimiento:
El rendimiento teórico se determina de la siguiente manera:
50.05 g * 1 mol / 138.21 g / mol de C₇H₆O₃ * 1 mol de C₉H₈O₄ / 1 mol de C₇H₆O₃ * 180.157 g / mol de C₉H₈O₄ = 65.24 g de C₉H₈O₄
Porcentaje de rendimiento
Porcentaje de rendimiento = 84.99%
Por lo tanto, el porcentaje de rendimiento para la cantidad dada de ácido salicílico es 84.99%
<em>In English:</em>
<em>The balanced chemical eqaution for the reaction can be written as:</em>
<em>C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + HC₂H₃O₂</em>
<em>For the reaction shown above; The limiting reactant from the reaction is salicylic acid. Now; to calculate the percentage yield ; we are expected to first determine the theoretical yield of the reaction. </em>
<em>So; the formula for calculating the percentage yield </em><em> </em>
<em />
<em>The theoretical yield is determined as follows:</em>
<em>50.05 g * 1 mol/ 138.21 g/mol of C₇H₆O₃ * 1 mol of C₉H₈O₄/ 1 mol of C₇H₆O₃ * 180.157 g/mol of C₉H₈O₄ = 65.24 g of C₉H₈O₄ is produced</em>
<em />
<em>Percentage yield </em><em />
<em>Percentage yield = 84.99%</em>
<em />
<em>Thus, the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>