Answer:
Explanation:
The options are:
- In an isometric drawing, multiple angles and axes can be shown in one sketch.
- There is no room for detail in an isometric drawing, so the detail is shown in the orthographic projection.
- Only one sketch will be needed since all other previous designs will no longer be necessary.
- Computer programs will not be necessary to create the exact dimensions of the design.
Orthographic projections are in either the First or Third Angles but the angles are fixed and do not provide perspective view. Isometric drawings are perspective views from different angles.
So Ethan's skill is valuable because "In an isometric drawing, multiple angles and axes can be shown in one sketch."
Answer:
a) 0.684
b) 0.90
Explanation:
Catalyst
EO + W → EG
<u>a) calculate the conversion exiting the first reactor </u>
CAo = 16.1 / 2 mol/dm^3
Given that there are two stream one contains 16.1 mol/dm^3 while the other contains 0.9 wt% catalyst
Vo = 7.24 dm^3/s
Vm = 800 gal = 3028 dm^3
hence Im = Vin/ Vo = (3028 dm^3) / (7.24dm^3/s) = 418.232 secs = 6.97 mins
next determine the value of conversion exiting the reactor ( Xai ) using the relation below
KIm =
------ ( 1 )
make Xai subject of the relation
Xai = KIm / 1 + KIm --- ( 2 )
<em>where : K = 0.311 , Im = 6.97 ( input values into equation 2 )</em>
Xai = 0.684
<u>B) calculate the conversion exiting the second reactor</u>
CA1 = CA0 ( 1 - Xai )
therefore CA1 = 2.5438 mol/dm^3
Vo = 7.24 dm^3/s
To determine the value of the conversion exiting the second reactor ( Xa2 ) we will use the relation below
XA2 = ( Xai + Im K ) / ( Im K + 1 ) ----- ( 3 )
<em> where : Xai = 0.684 , Im = 6.97, and K = 0.311 ( input values into equation 3 )</em>
XA2 = 0.90
<u />
<u />
<u />
Y = a (b)^t/p
y is total money
a is original amount
b is growth / decay factor
t is time
p is the frequency of every growth or decay
15131.76 = 11613 x 1.08^x
15131.76 / 11613 = 1.08^x
1.303… = 1.08^x
log1.303…. = xlog1.08
x = 3.43902165741 years