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sweet-ann [11.9K]
4 years ago
6

The virial equation for nitrogen gas is PV=RT(1+4.41×10-4P). Using the virial equation of state for nitrogen at 600 K, calculate

The fugacity of nitrogen at 200 atm and 600 K. The fugacity of nitrogen at 1 atm and 600 K. The change in the Gibbs free energy caused by a compression of 1 mole of nonideal nitrogen gas at 600 K from 1 to 200 atm. The change in the Gibbs free energy caused by a compression of 1 mole of ideal nitrogen gas at 600 K from 1 to 200 atm. What is the magnitude of the contribution to (c) caused by the nonideality of nitrogen?

Engineering
1 answer:
Sonja [21]4 years ago
8 0

Answer:

(a)fugacity,f=218.44atm

(b) fugacity,f= 1.0004

(c) 44241.906kj/mol

(d)2642J/mol

(e)44215.485kJ/mol

Explanation:

Check attachments

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How much does the transportation sector contribute to current greenhouse gas emissions? Where do most of these emissions come fr
Mekhanik [1.2K]

Answer:

29 percent

Explanation:

The transportation sector is the highest contributing factor to greenhouse gas emissions in the world. Vehicles such as cars, motorcycles, airplanes, ships etc all emit these gases which causes global warming.

Electric cars is known not to little or zero direct emission and known to be safer. It however emits nitrogen oxide which is fog like in a very minute quantity.

6 0
3 years ago
Using Pascal’s Law and a hydraulic jack, you want to lift a 4,000 lbm rock. The large cylinder has a diameter of 6 inches.
jolli1 [7]

Answer:

a diameter of D₂ = 0.183 inches would be required

Explanation:

appyling pascal's law

P applied to the hydraulic jack = P required to lift the rock

F₁*A₁ = F₂*A₂

since A₁= π*D₁²/4 ,  A₂= π*D₂²/4

F₁*π*D₁²/4 = F₂* π*D₂²/4

F₁*D₁²=F₂*D₂²

D₂ = D₁ *√(F₁/F₂)

replacing values

D₂ = D₁ *√(F₁/F₂) =  6 in * √(120 lbf/(4000 lbm * 32.174 (lbf/lbm)) = 0.183 inches

6 0
3 years ago
Substance Specific Heat (cal/g°C) Specific Heat (J/g°C) water 1.00 4.18 steam 0.96 4.02 alcohol 0.59 2.47 ice 0.50 2.09 wood 0.4
Jobisdone [24]

Answer:

C) 43,2°C

Explanation:

<em>Sensible heat</em> is the amount of thermal energy that is required to change the temperature of an object, the equation for calculating the heat change is  given by:

Q=msΔT

where:

  • Q, heat that has been absorbed or realeased by the substance [J]
  • m, mass of the substance [g]
  • s, specific heat capacity [J/g°C]
  • ΔT, changes in the substance temperature [°C]

To solve the problem, we clear ΔT of the equation and then replace our data:

Q=890 [J],

m=16,6 [g],

s=2,74 [J/g°C]

Q=msΔT.......................ΔT=Q/ms

ΔT=\frac{890 J}{16,6g*2,47\frac{J}{gC}}=21,7°C

As:

ΔT=Tfinal-Tinitial

Tfinal=ΔT+Tinitial

Tfinal=21,7+21,5=43,2°C

The final temperature of the ethanol is 43,2°C.

4 0
4 years ago
What are the basic steps in the operation of a solar cell?
kati45 [8]

Answer:

Light is absorbed and knocks electrons loose. Loose electrons flow, creating a current. The current is captured and transferred to wires.

7 0
3 years ago
Propane is to be compressed from 0.4 MPa and 360 K to 4 MPa using a two-stage compressor. An interstage cooler returns the tempe
kow [346]

Answer:

a. 81 kj/kg

b. 420.625K

c.  101.24kj/kg

Explanation:

\frac{t2}{t1} =[\frac{p2}{p1} ]^{\frac{y-1}{y} }

t1 = 360

p1 = 0.4mpa

p2 = 1.20

y = 1.13

substitute these values into the equation

\frac{t2}{360} =[\frac{1.20}{0.4} ]^{\frac{1.13-1}{1.13} }

\frac{t2}{360} =[\frac{1.2}{0.4} ]^{0.1150}\\\frac{t2}{360} =1.1347

when we cross multiply

t2 = 360 * 1.1347

= 408.5

a. the work required in the firs compressor

w=c(t2-t1)

c=1.67x10³

t1 = 360

t2 = 408.5

w = 1670(408.5-360)

= 1670*48.5

= 80995 J

= 81KJ/kg

b. n=\frac{t2-t1}{t'2-t1}

n = 80%

t2 = 408.5

t1 = 360

0.80 = 408.5-360 ÷ t'2-360

0.80 =\frac{48.5}{t'2-360}

cross multiply to get the value of t'2

0.80(t'2-360) = 48.5

0.80t'2 - 288 = 48.5

0.8t'2 = 48.5+288

0.8t'2 = 336.5

t'2 = 336.5/0.8

= 420.625

this is the temperature at the exit of the first compressor

c. cooling requirement

w = c(t2-t1)

= 1.67x10³(420.625-360)

= 1670*60.625

= 101243.75

= 101.24kj/kg

8 0
3 years ago
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