Answer:
The answers to your questions are given below
Explanation:
1. KClO3 => Potassium trioxochlorate (V)
Thermal decomposition of KClO3.
When we heat potassium trioxochlorate (V), KClO3, it will slip into two producing potassium chloride, KCl and oxygen gas, O2 as shown below:
2KClO3(s) —> 2KCl(s) + 3O2(g)
Note: the above reaction will occur faster and at a lower temperature in the presence of manganese (iv) oxide as catalyst.
2a. Determination of the number protons and neutrons in Nitrogen–14.
Nitrogen–14 has the following:
Mass number = 14
Atomic number = 7
Proton =?
Neutron =?
Atomic number of an atom is simply the proton number. Therefore,
Proton = Atomic number
Atomic number = 7
Proton = Atomic number = 7
Proton = 7
Mass number = Proton + Neutron
Mass number = 14
Proton = 7
Neutron =?
14 = 7 + Neutron
Collect like terms
Neutron = 14 – 7
Neutron = 7
Therefore, Nitrogen–14 has 7 protons and 7 neutrons.
2b. Determination of the number protons and neutrons in Nitrogen–15.
Nitrogen–15 has the following:
Mass number = 15
Atomic number = 7
Proton =?
Neutron =?
Atomic number of an atom is simply the proton number. Therefore,
Proton = Atomic number
Atomic number = 7
Proton = Atomic number = 7
Proton = 7
Mass number = Proton + Neutron
Mass number = 15
Proton = 7
Neutron =?
15 = 7 + Neutron
Collect like terms
Neutron = 15 – 7
Neutron = 8
Therefore, Nitrogen–15 has 7 protons and 8 neutrons.
