Answer:
12.44 g
Explanation:
2C4H10 + 13O2 = 8CO2 + 10H2O
n(C4H10) = m(C4H10)/M(C4H10) = 4.1 / 58g/mol = 0.0707 mol (excess).
n(O2) = m(O2)/M(O2) = 25.9 / 32g/mol = 0.809 mol (deficiency).
Since the ratio of O2 to octane is 13 : 2 we can divide 0.0707 by 2 to get 0.03535 and divide 0.809 by 13 to get 0.062.
mass of CO2 produced =
M = [0.0707 moles C4H10 x 8 moles CO2] / 2 moles C4H10 x 44 g CO2/mol
M = 0.5656/2 * 44
M = 0.2828 * 44
M = 12.44 of CO2
Answer:
It traveled for 4 seconds at a distance of about 4.1 meters. With a velocity of 10%.
Explanation:
a. 48.6 is magnesium and 32.0 is oxygen
b. 80.6
c. also 80.6
d. yes, because the product has equal mass to the reactants
Answer:
Magnesium loses two electrons.
Explanation:
- As clear from the reaction Mg converted from <em>Mg(s) to Mg²⁺</em>, so Mg converted from the oxidation state (0) to (2+).
<em>∴ Mg losses two electrons.</em>
- Cl⁻ remains as it is, so it is considered as a catalyst and neither loss nor gain any electrons.
<em>So, the correct choice is Magnesium loses two electrons.</em>
An electron with greater energy.
I hope this helps :)
