S ?
U 0m/s
V ?
A 0.1m/s^2
T 2min (120 sec)
S=ut+0.5at^2
S=0(120 sec)+0.5(0.1m/s^2)(120 sec)^2
S=720m
Distance double 720m*2=1440m
V^2=u^2+2as
V^2=(0)^2+2(0.1 m/s^2)(1440m)
V^2=288
V= square root of 288=12 root 2=16.97 to 2 decimal places
Answer:
Time period of the osculation will be 0.0671 sec
Explanation:
It is given a vertical spring is stretched by 4 cm
So change in length of the spring x = 4 cm = 0.04 m
Mass which is hung from it m = 12 gram = 0.012 kg
Sprig force will be equal to weight of the mass
So 

k = 244.7 N/m
Now new mass is m = 28 gram = 0.028 kg
So time period with new mass will be


Answer:
The answer should be <u>WORK </u>
<em>(Hope this Helps)</em>
Explanation:
work is equal to the product of force and distance.
W=F*S
W=Work
F=Force applied
S=Distance
Answer:
0.002372187708 kg
Explanation:
Each atom of Uranium 235 releases 200 MeV = 200×10⁶×1.60218×10⁻¹⁹
= 200×1.60218×10⁻¹³ Joule
Number of atoms in a 2.6 kg sample mass = (2.6/0.235)×6.02214076×10²³
⇒Number of atoms in a 2.6 kg sample mass = 66.627×10²³ atoms
Change in energy = Change in mass / (speed of light)²
ΔE = Δmc²
⇒200×1.60218×10⁻¹³×66.627×10²³ = Δm×(3×10⁸)²
⇒Δm = 200×1.60218×10⁻¹³×66.627×10²³/(3×10⁸)²
⇒Δm = 2372.187708×10⁻⁶ kg
∴Change in mass = 0.002372187708 kg