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Kay [80]
3 years ago
8

In a nuclear reactor, each atom of uranium (of atomic mass 235 u) releases about 200 MeV when it fissions. What is the change in

mass when 2.60 kg of uranium-235 is fissioned?
Physics
1 answer:
Ket [755]3 years ago
7 0

Answer:

0.002372187708 kg

Explanation:

Each atom of Uranium 235 releases 200 MeV = 200×10⁶×1.60218×10⁻¹⁹

= 200×1.60218×10⁻¹³ Joule

Number of atoms in a 2.6 kg sample mass = (2.6/0.235)×6.02214076×10²³

⇒Number of atoms in a 2.6 kg sample mass = 66.627×10²³ atoms

Change in energy = Change in mass / (speed of light)²

ΔE = Δmc²

⇒200×1.60218×10⁻¹³×66.627×10²³ = Δm×(3×10⁸)²

⇒Δm = 200×1.60218×10⁻¹³×66.627×10²³/(3×10⁸)²

⇒Δm = 2372.187708×10⁻⁶ kg

∴Change in mass = 0.002372187708 kg

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In which graph is acceleration the slope?
olga2289 [7]

Answer:

<em>Velocity</em><em> </em><em>-</em><em>time</em><em> </em><em>graph</em><em> </em>

Explanation:

hope it helps ✌️✌️

4 0
2 years ago
Read 2 more answers
The latin word (Cirro) mean that the clouds are in high level <br><br> True of false?
Ivahew [28]

Answer:

False

Explanation:

The Latin word "Cirro" means "curly" or "curl of hair" as in a cirrocumulus cloud. Cirrocumulus clouds are wispy clouds, and while they do appear high in the sky, the word "cirro" does not mean high in level.

Therefore, the answer is False.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0
3 years ago
Read 2 more answers
An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric
8090 [49]

Answer:

1.) 11 km/s

2.) 9.03 × 10^-5 metres

Explanation:

Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

Electron q = 1.6×10^-19 C

Electron mass = 9.11×10^-31 Kg

(a) What is the speed of the electron 1.3 ns after entering this region?

E = F/q

F = Eq

Ma = Eq

M × V/t = Eq

Substitute all the parameters into the formula

9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

V = 7.68×10^-18 /7.0×10^-22

V = 10971.43 m/s

V = 11 Km/s approximately

(b) How far does the electron travel during the 1.3 ns interval?

The initial velocity U = 64 km/s

S = ut + 1/2at^2

S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

S =8.32×10^-5 + 7.13×10^-6

S = 9.03 × 10^-5 metres

3 0
3 years ago
An electron in the n = 7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 397 nm. what is the value
Dimas [21]

Answer:

n_f=2

Explanation:

It is given that,

Initially, the electron is in n = 7 energy level. When it relaxes to a lower energy level, emitting light of 397 nm. We need to find the value of n for the level to which the electron relaxed. It can be calculate using the formula as :

\dfrac{1}{\lambda}=R(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})

\dfrac{1}{397\times 10^{-9}\ m}=R(\dfrac{1}{n_f^2}-\dfrac{1}{(7)^2})

R = Rydberg constant, R=1.097\times 10^7\ m^{-1}

\dfrac{1}{397\times 10^{-9}\ m}=1.097\times 10^7\ m^{-1}\times (\dfrac{1}{n_f^2}-\dfrac{1}{(7)^2})

Solving above equation we get the value of final n is,

n_f=2.04

or

n_f=2

So, it will relax in the n = 2. Hence, this is the required solution.        

6 0
3 years ago
Read 2 more answers
What are the change in internal energy if 250 j of hear is added to a system of 80 j of work is done by the system
Sphinxa [80]

Answer:

Explanation:

dU= dq+w

dU is change in internal energy of the system

dq is the amount heat added or released by the system which be positive or negative respectivelý

And w is the amount of work done by the system or on the system which will be positive or negative respectively.

Hence,

dU= 250+80= 330 J

The change will be positive

5 0
3 years ago
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