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Elza [17]
4 years ago
7

If the line segment connecting point P (5,2) to point R (3,6) is rotated 90 degrees counter clockwise about point R what is the

slope of the original segment PR?

Mathematics
1 answer:
Vlad [161]4 years ago
3 0
Given:
P (5, 2) 
R (3, 6)

finding the slope of a straight line.

m = y1 - y2 / x1-x2 = (2-6) / (5-3) = -4 / 2 = -2

The slope of the original segment PR is -2. 

I graphed the changes. The new coordinate of P is (7,8)

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Help needed ! 13 - 2(2x + 1) = 1 ?
kirill115 [55]

Answer:

x = ¹⁰⁄₄,⁵⁄₂, or 2.5

Step-by-step explanation:

Given: 13 - 2(2x + 1) = 1

1. Distribute -2 through the parentheses:

⇒ 13 - 2(2x + 1) = 1

⇒ 13 + (-2)(2x) + (-2)(1) = 1

13 - 4x - 2 = 1

2. Combine like terms:

⇒ 13 - 4x - 2 = 1

⟹ 11 - 4x = 1

3. Subtract 11 from both sides:

⇒ 11 - 11 - 4x = 1 - 11

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4. Divide both sides by -4:

⇒ -4x ÷ -4 = -10 ÷ -4

⟹ x = ¹⁰⁄₄,⁵⁄₂, or 2.5

5. Check your work:

⇒ 13 - 2(2x + 1) = 1

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Learn more here:

brainly.com/question/17139226

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