Answer:
Height h = 37.8 m
Explanation:
Given
:
Velocity of car (v) = 98 km / h
Acceleration of gravity = 9.8 m/s²
Computation:
Acceleration of gravity = 9.8 m/s²
Acceleration of gravity = (98)(1,000 m / 3,600 s)
Acceleration of gravity = 27.22 m/s
By using law of conservation of energy
;
(1/2)mv² = mgh
h = v² / 2g
h = 27.22² / 2(9.8)
Height h = 37.8 m
Answer:
change waterslide according to question. and you are good to go. check photo for solve
That seems like a statement more than a question. Where's the question?
Answer:
a) x = 4.33 m
, b) w = 2 rad / s
, f = 0.318 Hz
, c) a = - 17.31 cm / s²,
d) T = 3.15 s, e) A = 5.0 cm
Explanation:
In this exercise on simple harmonic motion we are given the expression for motion
x = 5 cos (2t + π / 6)
they ask us for t = 0
a) the position of the particle
x = 5 cos (π / 6)
x = 4.33 m
remember angles are in radians
b) The general form of the equation is
x = A cos (w t + Ф)
when comparing the two equations
w = 2 rad / s
angular velocity and frequency are related
w = 2π f
f = w / 2π
f = 2 / 2pi
f = 0.318 Hz
c) the acceleration is defined by
a == d²x / dt²
a = - A w² cos (wt + Ф)
for t = 0
, we substitute
a = - 5,0 2² cos (π / 6)
a = - 17.31 cm / s²
d) El period is
T = 1/f
T= 1/0.318
T = 3.15 s
e) the amplitude
A = 5.0 cm
If you only know its speed, that's not enough information to catch it. You could even chase it at DOUBLE that speed, and you'd never catch it if you were chasing in the wrong direction.
You also have to know the DIRECTION the runaway car is going, so that you can chase in the same direction.
Now that you know its speed AND direction, you know its velocity. You need that information to have any chance of catching it.