Answer: 259.2 KJ
Explanation:
The formula calculate work don in a circuit is given by :-
, where Q is charge and V is the potential difference.
The formula to calculate charge in circuit :-
, where I is current and t is time.
Given : Current : 
Potential difference : 
Time : 
Now, 
Then, 
Hence, the work done = 259.2 KJ
the answer is ( True ) .
the current is the same in series circuits .
The centripetal acceleration is responsible
for the artificial gravity because the acceleration of an object moving in constant
circular motion causing from net external force is called centripetal
acceleration. It defines to the center or seeking the center.
Given the following:
Cylindrical space station
diameter = 275 meters; 137.5
meters for the radius
Standard gravity =
9.80665 m/s²
Using the formula:
w² x r =g
w² = g / r
w² = 9.80665 m/s²
/ 137.5 m
w² = 9.80665 m/s²
/ 137.5 m
w² = 0.0713 s²
Then take the roots
w = 0.267 this is radians per
second / 2 x (3.1416 which is the pi)
w = 0.0424 rps convert to rpm
w = 0.0424 r/s (1minute / 60
seconds)
w = 7.08 x 10⁻⁴ revolutions per minute
Answer:
gas, metal
Explanation:
The three states of by which hydrogen is found in Jupiter is made up of:
- Gaseous hydrogen
- liquid hydrogen
- liquid metal hydrogen
This is also the same states found in Saturn too.
The pressure inside the largest planet in our solar system is very great.
- Hydrogen and helium makes up the entirety of the planet Jupiter.
- It has been discovered that inside this planet, hydrogen often occurs as gas, liquid and metal
- This is often attributed to the huge amount of pressure in the planet.
Complete Question
A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?
Answer:
The values is 
Explanation:
From the question we are told that
The diameter is 
The charge is 
The distance from the center is 
Generally the radius is mathematically represented as
=> 
=> 
Generally electric field is mathematically represented as
![E = \frac{Q}{ 2\epsilon_o } [1 - \frac{k}{\sqrt{r^2 + k^2 } } ]](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7BQ%7D%7B%202%5Cepsilon_o%20%7D%20%5B1%20-%20%5Cfrac%7Bk%7D%7B%5Csqrt%7Br%5E2%20%2B%20%20k%5E2%20%7D%20%7D%20%5D)
substituting values
![E = \frac{4.4 *10^{-9}}{ 2* (8.85*10^{-12}) } [1 - \frac{(1.00 *10^{-4})}{\sqrt{(0.06)^2 + (1.0*10^{-4})^2 } } ]](https://tex.z-dn.net/?f=E%20%3D%20%20%5Cfrac%7B4.4%20%2A10%5E%7B-9%7D%7D%7B%202%2A%20%288.85%2A10%5E%7B-12%7D%29%20%7D%20%5B1%20-%20%5Cfrac%7B%281.00%20%2A10%5E%7B-4%7D%29%7D%7B%5Csqrt%7B%280.06%29%5E2%20%2B%20%20%281.0%2A10%5E%7B-4%7D%29%5E2%20%7D%20%7D%20%5D)
