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2 years ago

A box of jello has a mass of 250 g. How many boxes must be bought to have 1 Kg of jello? *

Chemistry

1 answer:

zhuklara [117]2 years ago

8 0

Answer:

Number of boxes = 4

Explanation:

Given:

Mass of one box of jello = 250 grams

Total quantity want to purchase = 1 kg = 1 × 1,000 gram = 1,000 grams

Find:

Number of boxes in 1,000 grams = ?

Computation:

Number of boxes = Total quantity want to purchase / Mass of one box of jello

Number of boxes = 1,000 / 250

Number of boxes = 4

Therefore, 4 boxes of jello must be purchase to get 1 kg of Jello.

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4 molecules of glucose has how many carbon hydrogen and oxygen

gavmur [86]

Answer:

24 carbons

48 hydrogens

24 oxygen

Explanation:

7 0

2 years ago

For the decomposition of calcium carbonate, consider the following thermodynamic data (Due to variations in thermodynamic values

In-s [12.5K]

Answer : The temperature in kelvins is, $T>1108.695K$

Explanation : Given,

$\Delta H$ = 178.5 KJ/mole = 178500 J/mole

$\Delta S$ = 161.0 J/mole.K

Gibbs–Helmholtz equation is :

$\Delta G=\Delta H-T\Delta S$

As per question the reaction is spontaneous that means the value of $\Delta G$ is negative or we can say that the value of $\Delta G$ is less than zero.

$\Delta$

The above expression will be:

$0>\Delta H-T\Delta S$

$T\Delta S>\Delta H$

$T>\frac{\Delta H}{\Delta S}$

Now put all the given values in this expression, we get :

$T>\frac{178500J/mole}{161.0J/mole.K}$

$T>1108.695K$

Therefore, the temperature in kelvins is, $T>1108.695K$

7 0

2 years ago

In a heat engine, 700 J of heat enters the system, and the piston does 400 J of work. What is the final internal (thermal) energ

Vitek1552 [10]

The first law of thermodynamics characterises the two types of energy transfer, as heat and as thermodynamic. The final internal (thermal) energy of the system is 1,500 J.

<h3>What is internal energy?</h3>

The energy present in a system itself for conducting reactions is called internal energy.

Given,

Heat entering system (Q) = 700 J
Work done by the piston (W) = 400
Initial energy $(\rm U_{1})$ = 1200 J

According to the <u>first law of thermodynamics</u>:

$\rm Q = \Delta U + W$

Substituting values in the above equation:

$\begin{aligned}\rm Q &= \rm U_{2} - U_{1} + W\\\\\rm U_{2} &= \rm Q - W + U_{1}\\\\\rm U_{2} &= 700 - 400 + 1200\\\\&= 1500 \;\rm J\end{aligned}$

Therefore, option D. 1500 J is the final energy.

Learn more about internal energy here:

brainly.com/question/2602565

4 0

1 year ago

Read 2 more answers

Equation is balanced already

mojhsa [17]

Answer:

1.) 13 g C₄H₁₀

2.) 41 g CO₂

Explanation:

To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.

Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)

Molar Mass (C₄H₁₀): 58.124 g/mol

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O

48 g O₂ 1 mole 2 moles C₄H₁₀ 58.124 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole

= 13 g C₄H₁₀

48 g O₂ 1 mole 8 moles CO₂ 44.007 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole

= 41 g CO₂

6 0

1 year ago

A cat travels 240 meters in 30 seconds, and a sprinter travels 100 meters in 9.5 seconds. Which is traveling faster, the cat or

joja [24]

Answer:

The cat

Explanation:

1) You need to find how many meters per second each thing is sprinting, so you can divide the meters by seconds for each.

$\frac{240}{30} = 8 m/s\\\frac{100}{9.5} = around 10.5 m/s$

2) Per second, the sprinter is able to achieve 8 meters, while the cat can do around 10.5 meters. 10.5 is greater than 8, making the cat faster than the sprinter.

4 0

1 year ago